Moving Charges and Magnetism
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The magnetic force depends on v which depends on the inertial frame of reference. Does then the magnetic force differ from inertial frame to frame? Is it reasonable that-the net acceleration has a different value indifferent frames of reference?
The magnetic force depends on v which depends on the inertial frame of reference. Does then the magnetic force differ from inertial frame to frame? Is it reasonable that-the net acceleration has a different value indifferent frames of reference?
This is a Short Answer Type Questions as classified in NCERT Exemplar
Explanation- yes, the magnetic force differ from inertial frame to frame. The magnetic force is frame dependent.
The net acceleration which comes into existing out of this is however, frame independent for inertial frames.
Show that a force that does no Work must be a velocity dependent force.
Show that a force that does no Work must be a velocity dependent force.
This is a Short Answer Type Questions as classified in NCERT Exemplar
Explanation- dW=F.dl=0
As dl = vdt
dW= Fvdt
dW= f.v=0
Five long wires A, B, C, D and E, each carrying current I are arranged to form edges of a pentagonal prism as shown in figure. Each carries current out of the plane of paper.
(a) What will be magnetic induction at a point on the axis 0? Axis is at a distance R from each wire.
(b) What will be the field if current in one of the wires (say A) is switched off?
(c) What if current in one of the wire (say A) is reversed?

Five long wires A, B, C, D and E, each carrying current I are arranged to form edges of a pentagonal prism as shown in figure. Each carries current out of the plane of paper.
(a) What will be magnetic induction at a point on the axis 0? Axis is at a distance R from each wire.
(b) What will be the field if current in one of the wires (say A) is switched off?
(c) What if current in one of the wire (say A) is reversed?

This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- (a) Suppose the five wires A, B, C, D and E be perpendicular to the plane of paper at locations as shown in figure.
Thus, magnetic field induction due to five wires will be represented by various sides of a
closed pentago
A multirange current meter can be constructed by using a galvanometer circuit as shown in figure. We want a current meter that can measure 10 mA, 100 mA and 1 mA using a galvanometer of resistance 10 Ω and that produces maximum deflection for current of 1 mA. Find S1 ,S2 and S3 that have to be used.

A multirange current meter can be constructed by using a galvanometer circuit as shown in figure. We want a current meter that can measure 10 mA, 100 mA and 1 mA using a galvanometer of resistance 10 Ω and that produces maximum deflection for current of 1 mA. Find S1 ,S2 and S3 that have to be used.

This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- iG (G) = (I1-IG) (S1+S2+S3) for I1= 10mA
iG (G+S1) = (I2-IG) (S2+S3) for I2= 100mA
iG (G+S1+S2) = (I3-IG) (S3) for I3= 1A
S1= 1W, S2= 0,1W and S3= 0.01W
Consider a circular current-carrying loop of radius R in the x-y plane with centre at origin. Consider the line integral ζ ( L ) = | | taken along z-axis.
(a) Show that ? ( ) monotonically increases with L.
(b) Use an appropriate Amperian loop to show that ζ ( ∞ ) = ?0? , where I is the current in the wire.
(c) Verify directly the above result.
(d) Suppose we replace the circular coil by a square coil of sides R carrying the same current I. What can you say about ζ ( L ) and ζ ( ∞ ) ?
Consider a circular current-carrying loop of radius R in the x-y plane with centre at origin. Consider the line integral ζ ( L ) = | | taken along z-axis.
(a) Show that ? ( ) monotonically increases with L.
(b) Use an appropriate Amperian loop to show that ζ ( ∞ ) = ?0? , where I is the current in the wire.
(c) Verify directly the above result.
(d) Suppose we replace the circular coil by a square coil of sides R carrying the same current I. What can you say about ζ ( L ) and ζ ( ∞ ) ?
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- B (z) points in the same direction on z-axis and hence, J (L) isa monotonically function of L so B.dl = B.dl as cos 0 = 1
(b) but when L
So B 1/r3
(c) the magnetic field due to a circula
<p>This is a Long Answer Type Questions as classified in NCERT Exemplar</p>
<p><strong>Explanation- </strong>B(z) points in the same direction on z-axis and hence , J(L) isa monotonically function of L so B.dl = B.dl as cos 0 = 1</p>
<p>(b) <math><mo>∫</mo><mrow><mrow><mi>B</mi><mo>.</mo><mi>d</mi><mi>l</mi><mo>=</mo><msub><mrow><mrow><mi>μ</mi></mrow></mrow><mrow><mrow><mi>o</mi></mrow></mrow></msub><mi>I</mi></mrow></mrow></math> but when L <math><mo>→</mo></math> <math><mi>∞</mi></math></p>
<p>So B <math><mo>∝</mo></math> 1/r<sup>3</sup></p>
<p>(c) the magnetic field due to a circular current carrying loop of radius in the xy plane with centre at origin at any point lying at a distance of from origin.</p>
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<div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1742970473phpxObRU4_480x360.jpeg" media="(max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1742970473phpxObRU4.jpeg" alt="" width="178" height="117"></picture></div>
</div>
<p> </p>
<p>B= <math><mfrac><mrow><mrow><msub><mrow><mrow><mi>μ</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub><mi>I</mi><msup><mrow><mrow><mi>R</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup></mrow></mrow><mrow><mrow><mn>2</mn><msup><mrow><mrow><mo>(</mo><msup><mrow><mrow><mi>Z</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup><mo>+</mo><msup><mrow><mrow><mi>R</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup><mo>)</mo></mrow></mrow><mrow><mrow><mn>3</mn><mo>/</mo><mn>2</mn></mrow></mrow></msup></mrow></mrow></mfrac></math></p>
<p>Z=Rtan <math><mi>θ</mi></math></p>
<p>dz=Rsec<sup>2</sup> <math><mi>θ</mi><mi>d</mi><mi>θ</mi></math></p>
<p><math><msubsup><mo>∫</mo><mrow><mo>-</mo><mi>∞</mi></mrow><mrow><mi>∞</mi></mrow></msubsup><mrow><mrow><msub><mrow><mrow><mi>B</mi></mrow></mrow><mrow><mrow><mi>z</mi></mrow></mrow></msub><mi>d</mi><mi>z</mi></mrow></mrow><mo>=</mo><mfrac><mrow><mrow><msub><mrow><mrow><mi>μ</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub><mi>I</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></mfrac><msubsup><mo>∫</mo><mrow><mo>-</mo><mi>π</mi><mo>/</mo><mn>2</mn></mrow><mrow><mi>π</mi><mo>/</mo><mn>2</mn></mrow></msubsup><mrow><mrow><mi>c</mi><mi>o</mi><mi>s</mi><mi>θ</mi><mi>d</mi><mi>θ</mi></mrow></mrow></math> = <math><msub><mrow><mrow><mi>μ</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub><mi>I</mi></math></p>
Consider a circular current-carrying loop of radius R in the x-y plane with centre at origin. Consider the line integral ζ ( L ) = | | taken along z-axis.
(a) Show that 𝜁 ( ) monotonically increases with L.
(b) Use an appropriate Amperian loop to show that ζ ( ∞ ) = 𝜇0𝐼 , where I is the current in the wire.
(c) Verify directly the above result.
(d) Suppose we replace the circular coil by a square coil of sides R carrying the same current I. What can you say about ζ ( L ) and ζ ( ∞ ) ?
Consider a circular current-carrying loop of radius R in the x-y plane with centre at origin. Consider the line integral ζ ( L ) = | | taken along z-axis.
(a) Show that 𝜁 ( ) monotonically increases with L.
(b) Use an appropriate Amperian loop to show that ζ ( ∞ ) = 𝜇0𝐼 , where I is the current in the wire.
(c) Verify directly the above result.
(d) Suppose we replace the circular coil by a square coil of sides R carrying the same current I. What can you say about ζ ( L ) and ζ ( ∞ ) ?
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- B (z) points in the same direction on z-axis and hence, J (L) isa monotonically function of L so B.dl = B.dl as cos 0 = 1
(b) but when L
So B 1/r3
(c) the magnetic field due to a circula
A uniform conducting wire of length 12a and resistance R is wound up as a current carrying coil in the shape of (i) an equilateral triangle of side a, (ii) a square of sides a, and (iii) a regular hexagon of sides a. The coil is connected to a voltage source V0. Find the magnetic moment of the coils in each case.
A uniform conducting wire of length 12a and resistance R is wound up as a current carrying coil in the shape of (i) an equilateral triangle of side a, (ii) a square of sides a, and (iii) a regular hexagon of sides a. The coil is connected to a voltage source V0. Find the magnetic moment of the coils in each case.
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- as we know magnetic moment = nIA
For equilateral triangle M= nIA= 4I ( )
M= Ia2
For square, n=3 so total length of wire is 12a
M= nIA= 3I (a2) = 3Ia2
For regular hexagon of side a, n=2 so total length = 12a
M=
An electron and a positron are released from (0, 0, 0) and (0, 0, 1.5R) respectively, in a uniform magnetic field B = B0i, each with an equal momentum of magnitude p = eBR. Under what conditions on the direction of momentum will the orbits be non-intersecting circles?
An electron and a positron are released from (0, 0, 0) and (0, 0, 1.5R) respectively, in a uniform magnetic field B = B0i, each with an equal momentum of magnitude p = eBR. Under what conditions on the direction of momentum will the orbits be non-intersecting circles?
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- Since, B is along the x-axis, for a circular orbit the momenta of the two particles are in the y-z plane. Let P1 and P2 be the momentum of the electron and positron, respectively. Both traverse a circle of radius R of o
A rectangular conducting loop consists of two wires on two opposite sides of length l joined together by rods of length d. The wires each are of the same material but with cross-sections differing by a factor of 2. The thicker wire has a resistance R and the rods are of low resistance, which in turn are connected to a constant voltage source V0. The loop is placed in a uniform magnetic field B at 45° to its plane. Find T, the torque exerted by the magnetic field on the loop about an axis through the centres of rods.
A rectangular conducting loop consists of two wires on two opposite sides of length l joined together by rods of length d. The wires each are of the same material but with cross-sections differing by a factor of 2. The thicker wire has a resistance R and the rods are of low resistance, which in turn are connected to a constant voltage source V0. The loop is placed in a uniform magnetic field B at 45° to its plane. Find T, the torque exerted by the magnetic field on the loop about an axis through the centres of rods.
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- the thicker wire has a resistance R, then the other wire has a resistance @R as the wires are of the same material but different area

