Moving Charges and Magnetism

Get insights from 125 questions on Moving Charges and Magnetism, answered by students, alumni, and experts. You may also ask and answer any question you like about Moving Charges and Magnetism

  • 125

    Questions

  • 0

    Discussions

  • 0

    Active Users

  • 0

    Followers

Have a question about Moving Charges and Magnetism? Ask our experts

Ask Your Question

Keep it short & simple. Type complete word. Avoid abusive language.

New answer posted•a year ago
S
a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- yes, the magnetic force differ from inertial frame to frame. The magnetic force is frame dependent.

The net acceleration which comes into existing out of this is however, frame independent for inertial frames.

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- dW=F.dl=0

As dl = vdt

dW= Fvdt

dW= f.v=0

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- (a) Suppose the five wires A, B, C, D and E be perpendicular to the plane of paper at locations as shown in figure.

Thus, magnetic field induction due to five wires will be represented by various sides of a

closed pentago

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- iG (G) = (I1-IG) (S1+S2+S3) for I1= 10mA

iG (G+S1) = (I2-IG) (S2+S3) for I2= 100mA

iG (G+S1+S2) = (I3-IG) (S3) for I3= 1A

S1= 1W, S2= 0,1W and S3= 0.01W

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
New question posted•a year ago

<p>This is a Long Answer Type Questions as classified in NCERT Exemplar</p> <p><strong>Explanation-&nbsp;</strong>B(z) points in the same direction on z-axis and hence , J(L) isa monotonically function of L so B.dl = B.dl as cos 0 = 1</p> <p>(b)&nbsp;<math><mo>∫</mo><mrow><mrow><mi>B</mi><mo>.</mo><mi>d</mi><mi>l</mi><mo>=</mo><msub><mrow><mrow><mi>μ</mi></mrow></mrow><mrow><mrow><mi>o</mi></mrow></mrow></msub><mi>I</mi></mrow></mrow></math>&nbsp;but when L&nbsp;<math><mo>→</mo></math>&nbsp;<math><mi>∞</mi></math></p> <p>So B&nbsp;<math><mo>∝</mo></math> 1/r<sup>3</sup></p> <p>(c) the magnetic field due to a circular current carrying loop of radius in the xy plane with centre at origin at any point lying at a distance of from origin.</p> <div> <div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1742970473phpxObRU4_480x360.jpeg" media="(max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1742970473phpxObRU4.jpeg" alt="" width="178" height="117"></picture></div> </div> <p>&nbsp;</p> <p>B=&nbsp;<math><mfrac><mrow><mrow><msub><mrow><mrow><mi>μ</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub><mi>I</mi><msup><mrow><mrow><mi>R</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup></mrow></mrow><mrow><mrow><mn>2</mn><msup><mrow><mrow><mo>(</mo><msup><mrow><mrow><mi>Z</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup><mo>+</mo><msup><mrow><mrow><mi>R</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup><mo>)</mo></mrow></mrow><mrow><mrow><mn>3</mn><mo>/</mo><mn>2</mn></mrow></mrow></msup></mrow></mrow></mfrac></math></p> <p>Z=Rtan&nbsp;<math><mi>θ</mi></math></p> <p>dz=Rsec<sup>2</sup> <math><mi>θ</mi><mi>d</mi><mi>θ</mi></math></p> <p><math><msubsup><mo>∫</mo><mrow><mo>-</mo><mi>∞</mi></mrow><mrow><mi>∞</mi></mrow></msubsup><mrow><mrow><msub><mrow><mrow><mi>B</mi></mrow></mrow><mrow><mrow><mi>z</mi></mrow></mrow></msub><mi>d</mi><mi>z</mi></mrow></mrow><mo>=</mo><mfrac><mrow><mrow><msub><mrow><mrow><mi>μ</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub><mi>I</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></mfrac><msubsup><mo>∫</mo><mrow><mo>-</mo><mi>π</mi><mo>/</mo><mn>2</mn></mrow><mrow><mi>π</mi><mo>/</mo><mn>2</mn></mrow></msubsup><mrow><mrow><mi>c</mi><mi>o</mi><mi>s</mi><mi>θ</mi><mi>d</mi><mi>θ</mi></mrow></mrow></math>&nbsp;=&nbsp;<math><msub><mrow><mrow><mi>μ</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub><mi>I</mi></math></p>

3 Views|Posted a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- as we know magnetic moment = nIA

For equilateral triangle M= nIA= 4I ( 34a2 )

M= Ia23

For square, n=3 so total length of wire is 12a

M= nIA= 3I (a2) = 3Ia2

For regular hexagon of side a, n=2 so total length = 12a

M=

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- Since, B is along the x-axis, for a circular orbit the momenta of the two particles are in the y-z plane. Let P1 and P2 be the momentum of the electron and positron, respectively. Both traverse a circle of radius R of o

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago