Ncert Solutions Chemistry Class 11th
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New answer posted
6 months agoContributor-Level 10
9.16. (i) BeH2< TiH2 < CaH2
(ii) LiH (iii) F—F < HH < DD (iv) H2O < MgH2
New answer posted
6 months agoContributor-Level 10
9.15. No. Because if saline hydrides react with water the reaction will be highly exothermic thus the hydrogen evolved in this case can catch fire. CO2 cannot be used as fire extinguisher because CO2 will get absorbed in alkali metal hydroxides.
New answer posted
6 months agoContributor-Level 10
9.14. HF is expected to have the highest magnitude of hydrogen bonding since, fluorine is most electronegative. Therefore, HF is the most polar.
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6 months agoContributor-Level 10
9.13. When hydrogen is burnt in oxygen the reaction is highly exothermic, it produces very high temperature nearly 4000°C which is used for cutting and welding purposes.
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6 months agoContributor-Level 10
9.12. Metallic hydrides are useful for ultra-purification of dihydrogen and as dihydrogen storage media. In metallic hydrides, hydrogen is adsorbed as H-atoms. Due to the adsorption of H atoms the metal lattice expands and become unstable. Thus, when metallic hydride is heated, it decomposes to form hydrogen and finely divided metal. The hydrogen evolved can be used as fuel.
New answer posted
6 months agoContributor-Level 10
9.11. Those hydrides which do not have fix composition are called non-stoichiometric hydrides, and the composition varies with temperature and pressure. This type of hydrides is formed by d- and f-block elements. They cannot be formed by alkali metals because alkali metal hydrides form ionic hydrides.
New answer posted
6 months agoContributor-Level 10
9.10. Carbon hydrides of the type CnH2n+2 are electron precise hydrides. Because they have atom with exact number of electrons to form covalent bonds. Thus, they do not behave as Lewis acid or base. Since they have no tendency to accept or lose electrons.
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6 months agoContributor-Level 10
9.9. It is expected to be a Lewis acid. They are likely to accept electrons to become stable. They can form coordinate bond with electron rich compound.
2NaH(s) + B2H6 (g) → 2Na+[BH4]- (s)
&n
New answer posted
6 months agoContributor-Level 10
9.8. (i) Electron deficient hydrides: Compounds in which central atom has incomplete octet, are called electron deficient hydrides. For example, BeH2, BH3 are electron deficient hydrides.
(ii) Electron precise hydrides: Those compounds in which exact number of electrons are present in central atom or the central atom contains complete octet are called precise hydrides e.g., CH4, SiH4, GeH4 etc. are precise hydrides.
(iii) Electron rich hydrides: Those compounds in which central atom has one or more lone pair of excess electrons are called electron rich hydrides, e.g., NH3, H2O.
New answer posted
6 months agoContributor-Level 10
9.7. This is due to its small atomic size and small bond length (74 pm) of H-H bond.H? H bond has very high bond enthalpy (435.9 kJ/mol) which results in low reactivity at room temperature. The reactivity is increased at high temperature or in presence of catalyst. Under these conditions, hydrogen reacts with many metals and non-metals to form hydrides.
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