Ncert Solutions Chemistry Class 11th
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12.38. Which of the following carbocation is most stable? (Intermediate)
12.38. Which of the following carbocation is most stable? (Intermediate)
(b) Is the most stable since it is a tertiary carbocation.
Upvote 
12.37. In Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:
(a) Na4[Fe(CN)6] (b)Fe4[Fe(CN)6]3
(c) Fe2[Fe(CN)6] (d)Fe3[Fe(CN)6]4 . (Intermediate)
12.37. In Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:
(a) Na4[Fe(CN)6] (b)Fe4[Fe(CN)6]3
(c) Fe2[Fe(CN)6] (d)Fe3[Fe(CN)6]4 . (Intermediate)
(b) Iron (III) hexacyanidoferrate (II) (or ferriferrocyanide) Fe4 [Fe (CN)6]3 is the correct answer.
Upvote <p><strong>12.36. In the organic compound CH2 = CH – CH2 – CH2 – C ≡ CH, the pair of hybridised orbitals involved in the formation of: C2 – C3 bond is:</strong></p>
<p><strong>(a) sp – sp<sup>2</sup> (b) sp – sp<sup>3</sup> (c) sp<sup>2</sup> – sp<sup>3</sup> (d) sp<sup>3</sup> – sp<sup>3</sup></strong></p>
12.35. In an estimation of sulphur by Carius method, 0.468 of an organic sulphur compound gave 0.668 g of barium sulphate. Find out the percentage of sulphur in the compound.
12.35. In an estimation of sulphur by Carius method, 0.468 of an organic sulphur compound gave 0.668 g of barium sulphate. Find out the percentage of sulphur in the compound.
Mass of the compound = 0.468 g
Mass of barium sulphate= 0.668 g
% of sulphur = 
Upvote 12.34. 0.3780 g of an organic compound gave 0.5740 g of silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound.
12.34. 0.3780 g of an organic compound gave 0.5740 g of silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound.
Mass of the compound = 0.3780 g
Mass of silver chloride = 0.5740 g
% of chlorine =
Upvote 12.33. A sample of 0.50 g of an organic compound was treated according to Kjeldahl’s method. The ammonia evolved was absorbed in 50 ml of 0.5M H2SO4. The residual acid required 60 ml of 0.5 M solution of NaOH for neutralization. Find the percentage composition of nitrogen in the compound.
12.33. A sample of 0.50 g of an organic compound was treated according to Kjeldahl’s method. The ammonia evolved was absorbed in 50 ml of 0.5M H2SO4. The residual acid required 60 ml of 0.5 M solution of NaOH for neutralization. Find the percentage composition of nitrogen in the compound.
Step I: Calculation of volume of unused acid i.e. V2 =?
V1 = Volume of NAOH solution required = 60 cm3
N1 = Normality of NaOH solution = ½ N
N2 = Normality of H2SO4 = 1N
Applying N1V1 = N2V2
½ N x 60 cm3 = 1N x V2
Or V2 = 30 cm3
Step II: calculation of volume of acid used
Volume of acid added =
Upvote 12.32. An organic compound contains 69% carbon and 4.8% hydrogen, the remainder being oxygen. Calculate the masses of carbon dioxide and water produced when 0.20 g of this compound is subjected to complete combustion.
12.32. An organic compound contains 69% carbon and 4.8% hydrogen, the remainder being oxygen. Calculate the masses of carbon dioxide and water produced when 0.20 g of this compound is subjected to complete combustion.
Step 1: Calculation of mass of CO2 produced
Mass of compound = 0.20 g
% of carbon = 69%
i.e. 12/44 x = Mass of Carbondioxide formed / Mass of Compound = 69/100
Therefore, mass of CO2formed = (69 x 44 x 0.20) / (12 x 100) = 0.506 g
Step 2: Calculation of mass of H2O produced
Mass of compound = 0.20 g
Upvote 12.31. Why is it necessary to use acetic acid and not sulphuric acid for acidification of sodium extract for testing sulphur by lead acetate test?
12.31. Why is it necessary to use acetic acid and not sulphuric acid for acidification of sodium extract for testing sulphur by lead acetate test?
It necessary to use acetic acid and not sulphuric acid for acidification of sodium extract for testing sulphur by lead acetate test because sulphuric acid will react with lead acetate to form a white precipitate of lead sulphate which will interfere in the test of sulphur.
Pb (OCOCH3)2 + H2SO4 →PbSO4
Upvote 12.30. Why is a solution of potassium hydroxide used to absorb carbon dioxide evolved during the estimation of carbon present in an organic compound?
12.30. Why is a solution of potassium hydroxide used to absorb carbon dioxide evolved during the estimation of carbon present in an organic compound?
CO2 is acidic in nature and therefore, it reacts with the strong base KOH to form K2CO3.
2KOH + CO2 ? K2CO3+ H2O.
Upvote 12.29. Will CCl4 give white precipitate of AgCl on heating it with silver nitrate? Give reason for your answer. (Intermediate)
12.29. Will CCl4 give white precipitate of AgCl on heating it with silver nitrate? Give reason for your answer. (Intermediate)
No. CCl4 is a completely non-polar covalent compound whereas AgNO3 is ionic in nature. Therefore, they are not expected to react and thus a white precipitate of silver chloride will not be formed.
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