Ncert Solutions Chemistry Class 11th
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New answer posted
6 months agoContributor-Level 10
(b) The difference in energy between the actual structure and the lowest energy resonance structure is called the resonance stabilisation energy or simply the resonance energy. The more the number of important contributing structures, the more is the resonance energy.
New answer posted
6 months agoContributor-Level 10
(c) In homolytic cleavage, one of the electrons of the shared pair in a covalent bond goes with each of the bonded atoms. Thus, in homolytic cleavage, the movement of a single electron takes place instead of an electron pair.
A heterolytic cleavage yields carbocations or carbanions, while a homolytic cleavage gives free radicals as reactive intermediate.
New answer posted
6 months agoContributor-Level 10
(b) It is a nucleophilic substitution reaction. KOH (aq) provides OH- ion for the nucleophile attack.
New answer posted
6 months agoContributor-Level 10
(b) Iron (III) hexacyanidoferrate (II) (or ferriferrocyanide) Fe4 [Fe (CN)6]3 is the correct answer.
New question posted
6 months agoNew answer posted
6 months agoContributor-Level 10
Mass of the compound = 0.468 g
Mass of barium sulphate= 0.668 g
% of sulphur = ![]()

New answer posted
6 months agoContributor-Level 10
Mass of the compound = 0.3780 g
Mass of silver chloride = 0.5740 g
% of chlorine =![]()

New answer posted
6 months agoContributor-Level 10
Step I: Calculation of volume of unused acid i.e. V2 =?
V1 = Volume of NAOH solution required = 60 cm3
N1 = Normality of NaOH solution = ½ N
N2 = Normality of H2SO4 = 1N
Applying N1V1 = N2V2
½ N x 60 cm3 = 1N x V2
Or V2 = 30 cm3
Step II: calculation of volume of acid used
Volume of acid added = 50 cm3
Volume of unused acid = 30 cm3
Volume of acid used = 50 – 30 = 20 cm3
Step III: Calculation of % of nitrogen
Mass of compound = 0.50 g
Volume of acid used = 20 cm3
Normality of acid used = 1 N
% of nitrogen = (1.4 x 20 x 1) / 0.50 = 56%
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