Ncert Solutions Chemistry Class 11th
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New answer posted
3 months agoContributor-Level 9
Number of sigma bonds are 10.
[Structure showing 10 sigma bonds in the molecule]
New answer posted
3 months agoContributor-Level 10
H? O (l) → H? O (g)
ΔH° = ΔU° + ΔngRT
ΔH° - ΔU° = ΔngRT
= 1 * 8.31 * 373
= 3099.63 J/mol
= 30.9963 * 10² J/mol
≈ 31 * 10² J/mol
New answer posted
3 months agoContributor-Level 10
Let volume of solution = x ml
So mass of solution = 1.2x
And mass of water = x gm
Mass of solute = 0.2x
Molality = (W_solute * 1000) / (M_solute * W_solvent) = (0.2x * 1000) / (40 * x) = 5 m
New answer posted
3 months agoContributor-Level 10
PCl? (g)? PCl? (g) + Cl? (g); Kc = 1.844
t=0: 3, 0, 0
equilibrium: 3-x, x
Kc = x² / (3-x) = 1.844
x² + 1.844x - 5.532 = 0
x = (-1.844 + √ (1.844² - 4 (1) (-5.532)/2 = (-1.844 + √25.528)/2 ≈ 1.604
At equilibrium number of moles of PCl? = (3 - 1.604) = 1.396 mol
= 1396 * 10? ³ mol
New answer posted
3 months agoContributor-Level 9
Oxidation states:
CrO? (+6), Fe?O? (+3), MnO? (+4), V?O? (+5), Cu?O (+1)
(a), (b), (c), (d), (e)
Order of oxidation numbers:
Cu?O < Fe?O? < MnO? < V?O? < CrO?. Hence correct order is; e < b < c < d < a
New answer posted
3 months agoContributor-Level 9
Same charge on adjacent atom is not stable. Hence the incorrect resonating structure is,
[Image of the incorrect resonance structure with adjacent positive charges]
New answer posted
3 months agoContributor-Level 10
q = +150 J
w = -200 J
∴ ΔU = q + w = 150 - 200 = -50 J
So, magnitude of ΔU is 50 J.
New answer posted
3 months agoContributor-Level 10
Due to small size Li have more polarizing power so most of the compound of Li are covalent.
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