Ncert Solutions Chemistry Class 11th
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Number of sigma bonds are 10.
[Structure showing 10 sigma bonds in the molecule]
Given below are two statements:
Statement I: None of the alkaline earth metal hydroxides dissolves in alkali.
Statement II: Solubility of alkaline earth metal hydroxides in water increases down the group.
In the light of the above statements, choose the most appropriate answer from the options given below:
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Given below are two statements:
Statement I: None of the alkaline earth metal hydroxides dissolves in alkali.
Statement II: Solubility of alkaline earth metal hydroxides in water increases down the group.
In the light of the above statements, choose the most appropriate answer from the options given below:
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Solubility of 2 group hydroxide increases down the group.
For water at 100°C and 1 bar, ΔᵥₐₚH - ΔᵥₐₚU = _______ × 10² J mol⁻¹ (Round off to the Nearest integer) [Use: R = 8.31 J mol⁻¹ K⁻¹] [Assume volume of H₂O(l) is much smaller than volume of H₂O(g). Assume H₂O(g) can be treated as an ideal gas]
For water at 100°C and 1 bar, ΔᵥₐₚH - ΔᵥₐₚU = _______ × 10² J mol⁻¹ (Round off to the Nearest integer) [Use: R = 8.31 J mol⁻¹ K⁻¹] [Assume volume of H₂O(l) is much smaller than volume of H₂O(g). Assume H₂O(g) can be treated as an ideal gas]
H? O (l) → H? O (g)
ΔH° = ΔU° + ΔngRT
ΔH° - ΔU° = ΔngRT
= 1 × 8.31 × 373
= 3099.63 J/mol
= 30.9963 × 10² J/mol
≈ 31 × 10² J/mol
The density of NaOH solution is 1.2 gm cm⁻³. The molality of this solution is _______ m. (Round off to the Nearest integer) [Use: Atomic masses: Na 23.0u O: 16.0 u H:1.0 u Density of H₂O: 1.0g cm⁻³]
The density of NaOH solution is 1.2 gm cm⁻³. The molality of this solution is _______ m. (Round off to the Nearest integer) [Use: Atomic masses: Na 23.0u O: 16.0 u H:1.0 u Density of H₂O: 1.0g cm⁻³]
Let volume of solution = x ml
So mass of solution = 1.2x
And mass of water = x gm
Mass of solute = 0.2x
Molality = (W_solute * 1000) / (M_solute * W_solvent) = (0.2x * 1000) / (40 * x) = 5 m
PCl₅ ⇌ PCl₃ + Cl₂ Kc = 1.844. 3.0 moles of PCl₅ is introduced in a 1L closed reaction vessel at 380K. The number of moles of PCl₅ at equilibrium is _______ × 10⁻³. (Round off to the Nearest integer)
PCl₅ ⇌ PCl₃ + Cl₂ Kc = 1.844. 3.0 moles of PCl₅ is introduced in a 1L closed reaction vessel at 380K. The number of moles of PCl₅ at equilibrium is _______ × 10⁻³. (Round off to the Nearest integer)
PCl? (g)? PCl? (g) + Cl? (g); Kc = 1.844
t=0: 3, 0, 0
equilibrium: 3-x, x
Kc = x² / (3-x) = 1.844
x² + 1.844x - 5.532 = 0
x = (-1.844 + √ (1.844² - 4 (1) (-5.532)/2 = (-1.844 + √25.528)/2 ≈ 1.604
At equilibrium number of moles of PCl? = (3 - 1.604) = 1.396 mol
= 1396 × 10? ³ mol
The correct order of following 3d metal oxides, according to their oxidation numbers is:
(a) CrO?
(b) Fe?O?
(c) MnO?
(d) V?O?
(e) Cu?O
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The correct order of following 3d metal oxides, according to their oxidation numbers is:
(a) CrO?
(b) Fe?O?
(c) MnO?
(d) V?O?
(e) Cu?O
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Oxidation states:
CrO? (+6), Fe?O? (+3), MnO? (+4), V?O? (+5), Cu?O (+1)
(a), (b), (c), (d), (e)
Order of oxidation numbers:
Cu?O < Fe?O? < MnO? < V?O? < CrO?. Hence correct order is; e < b < c < d < a
Which one among the following resonating structure is not correct?
[Images of four resonance structures of an N-oxide compound]
Which one among the following resonating structure is not correct?
[Images of four resonance structures of an N-oxide compound]
Same charge on adjacent atom is not stable. Hence the incorrect resonating structure is,
[Image of the incorrect resonance structure with adjacent positive charges]
A system does 200 J of work and at the same time absorbs 150 J of heat. The magnitude of the change in internal energy is __________ J. (Nearest integer)
A system does 200 J of work and at the same time absorbs 150 J of heat. The magnitude of the change in internal energy is __________ J. (Nearest integer)
q = +150 J
w = -200 J
∴ ΔU = q + w = 150 - 200 = -50 J
So, magnitude of ΔU is 50 J.
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: Lithium halides are some what covalent is nature.
Reason R: Lithium possess high polarisation capability.
In the light of the above statements, choose the most appropriate answer from the options given below:
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Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: Lithium halides are some what covalent is nature.
Reason R: Lithium possess high polarisation capability.
In the light of the above statements, choose the most appropriate answer from the options given below:
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Due to small size Li have more polarizing power so most of the compound of Li are covalent.
Match List- I with List-II:
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Match List- I with List-II:
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NaOH - Base
Be (OH)? - Amphoteric
Ca (OH)? - Base
B (OH)? - Acidic
Al (OH)? - Amphoteric




