Ncert Solutions Chemistry Class 11th

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

Angle of Ht – B – Ht > angle of Hb – B - Hb

Bond angle ∝ % S − C h a r a c t e r ∝ 1 % o f     P − c h a r a c t e r  

∠ H t B Ht is more so % P-Character is less.

 

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

NO3−+4H++3e−→NO+2H2O;ENO3−0=0.96V

Let[HNO3]=y  M

For same thermodynamic tendency of reduction

ENO3−/NO=ENO3−/NO2

0.96−0.0593logpNOy5=0.79−0.059logpNO2y3

Assume (pNO=pNO2=1bar)

0.17=−0.05911logpNO2y3+0.0593logpNOy5

=0.0593[logpNOy5−logp3NO2y9]=0.0593×log[pNOy5×y9p3NO2]=0.0593logy4

logy4=0.17×30.059⇒y=102.16

Comparing x = 2.16 and 2x = 4.32

Nearest integer is 4.

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New answer posted•a year ago
New answer posted•a year ago