Ncert Solutions Chemistry Class 11th

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

p K b ∝ 1 K b ∝ 1   Basic strength                                                                                       &nbs

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New answer posted•a year ago
S
a year ago

Theory based.                                                                                 

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New answer posted•a year ago
S
a year ago

Theory based.                                                                                 

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New question posted•a year ago
New answer posted•a year ago
S
a year ago

PV = nRT
n = PV/RT = (1 atm × 4×10? L) / (0.083 LatmK? ¹mol? ¹ × 300 K) = 1.6 × 10? mol
Mass = n × Molar Mass = 1.6 × 10? mol × 16 g/mol = 25.6 × 10? g ≈ 26 × 10? g

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New answer posted•a year ago
S
a year ago

Energy per second = 1000 J / 10 s = 100 J/s
Energy of one photon E = hc/λ = (6.626×10? ³? × 3×10? ) / (400×10? ) = 4.965 × 10? ¹? J
Number of electrons ejected = Total energy / Energy per photon = 100 / (4.965 × 10? ¹? ) = 20.14 × 10¹? ≈ 2 × 10²?

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New answer posted•a year ago
S
a year ago

A + B? 2C
Initial: 1, 1
At eq: 1-x, 1+2x
K = [C]²/ ( [A] [B]) = (1+2x)²/ (1-x)² = 100
(1+2x)/ (1-x) = 10
1+2x = 10-10x => 12x = 9 => x = 3/4
[C] = 1+2x = 1+2 (3/4) = 1+1.5 = 2.5M = 25 × 10? ¹M

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New answer posted•a year ago
S
a year ago

C? H? + 13/2 O? → 4CO? + 5H? O
1 mole C? H? (58 g) produces 5 mole H? O (90 g)
∴ 90 g H? O obtained from 58 g C? H?
∴ 72g H? O obtained from (58/90) × 72g = 46.4 g
= 464 × 10? ¹g

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New answer posted•a year ago