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Ncert Solutions Chemistry Class 11th

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4 months ago

Ncert Solutions Chemistry Class 11th Class 11th

A certain gas obeys $P (V_{m} - b) = R T .$ The value of ${(\frac{\partial z}{\partial P})}_{T} i s \frac{x b}{R T} .$ The value of x is------------.

(Integer answer) (Z : compressibility factor)

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Payal Gupta

Contributor-Level 10

$P (V_{m} - b) = R T$

$\frac{P V_{m}}{R T} - \frac{P b}{R T} = 1$

$Z = 1 + \frac{P b}{R T}$

${(\frac{\partial z}{\partial P})}_{T} = \frac{b}{R T}$

So, comparing with $\frac{x b}{R T}$

x = 1

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4 months ago

Ncert Solutions Chemistry Class 11th Class 11th

Statements about heavy water are given below

(a) Heavy water is used in exchange reaction for the study of reaction mechanisms.

(b) Heavy water is prepared by exhaustive electrolysis of water

(c) Heavy water has higher boiling point than ordinary water.

(d) Viscosity of H₂O is greater than D₂O.

Choose the most appropriate answer from the options given below:

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Payal Gupta

Contributor-Level 10

Heavy water (D₂O) is used in organic reaction to know the kinetics of reaction

Heavy water D₂O is obtained by repeated electrolysis of H₂O.

Heavy water has b.pt 101.4°C and ordinary water has b.pt 100°C

(b.pt of D₂O > b.pt of H₂O)

D₂O has more molecular mass than H₂O, so greater degree of association and hence greater b.pt and viscosity.

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4 months ago

Ncert Solutions Chemistry Class 11th Class 11th

Which of the following vitamin is helpful is delaying the blood clotting?

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Payal Gupta

Contributor-Level 10

Vitamin E is helpful in delaying blood clotting while vitamin K help blood clotting.

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5 months ago

Ncert Solutions Chemistry Class 11th Class 11th

4.5g of compound A (MW = 90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is * 10^-1. The value of x is_________ (Rounded off to the nearest integer)

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alok kumar singh

Contributor-Level 10

W = 4.5 g

M.W = 90

V = 250 ml

Using M = $\frac{W}{M . W * V} * 1000$

$M = \frac{4.5}{90 * 250} * 1000 = 0.2$

M = 2 * 10^-1 M

So, x = 2

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5 months ago

Ncert Solutions Chemistry Class 11th Class 11th

The NaNO₃ weighed out to make 50 mL of an aqueous solution containing 70.0mg Na⁺ per mL is…………. g. (Rounded off to the nearest integer)

[Given ; Atomic weight in g mol^-1 -Na : 23; N : 14; O : 16]

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Vishal Baghel

Contributor-Level 10

Mass of Na⁺ in 50 ml = 70 * 50 = 3500 mg

23000 mg of Na⁺ is present in 85000 mg of NaNO₃ (1 mole NaNO₃ contains 1 mole Na⁺)

$∴ 3500$ mg Na⁺ will be present in $\frac{85000}{23000} * 3500$

= 12934.78 mg

= 12.93478 gm

$≅ 13$

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5 months ago

Ncert Solutions Chemistry Class 11th Class 11th

The pH of ammonium phosphate solution, if pk_a of phosphoric acid and pK_b of ammonium hydroxide are 5.23 and 4.75 respectively, is…………….

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Vishal Baghel

Contributor-Level 10

pH = $\frac{1}{2} [p K_{w} + p K_{a} - p K_{b}]$ $\frac{}{}_{}_{}_{}$

$= \frac{1}{2} [14 + 4.75 - 5.23]$

$= 6.76 ≅ 7$

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5 months ago

Ncert Solutions Chemistry Class 11th Class 11th

A ball weighing 10g is moving with a velocity of 90 ms^-1. If the uncertainty in its velocity is 5%, then the uncertainty in its position is…………* 10^-33m. (Rounded off to the nearest integer)

[Given: h = 6.63 * 10^-34 Js]

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Vishal Baghel

Contributor-Level 10

Uncertainty in speed = 90 $* \frac{5}{100} = 4.5 m / s = Δ V$ $\frac{}{}$

$Δ x = \frac{h}{4 π m Δ V} = \frac{6.63 * 1 0^{- 34}}{4 * 3.14 * 1 0^{- 2} * 4.5} = 1.173 * 1 0^{- 33}$

the nearest integer is 1

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5 months ago

Ncert Solutions Chemistry Class 11th Class 11th

The gas released during anaerobic degradation of vegetation may lead to:

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alok kumar singh

Contributor-Level 10

Methane gas is produced during anaerobic degradation of vegetation that leads to global warming so considered as greenhouse gas like CO₂. Also it causes cancer.

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5 months ago

Ncert Solutions Chemistry Class 11th Class 11th

Which pair oxides in acidic in nature?

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Vishal Baghel

Contributor-Level 10

Oxide Nature

CaO Basic

B₂O₃ Acidic

SiO₂ Acidic

BaO Basic

N₂O

...more

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5 months ago

Ncert Solutions Chemistry Class 11th Class 11th

(A) HOCl + H₂O_2-> H₃O⁺ + Cl^- + O₂

(B) $I_{2} + H_{2} O_{2} + 2 O H^{-} \to 2 I^{-} + 2 H_{2} O + O_{2}$

Choose the correct option.

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alok kumar singh

Contributor-Level 10

In both reactions H₂O₂ act as reducing agent

In reaction (A) HOCl – O.A

H₂O₂ – R.A

In reaction (B) I₂ – O.A

H₂O₂ – R.A

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