Ncert Solutions Chemistry Class 11th
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Complete the following equations:
(i) PBS(s)+H2O2(aq) →
(ii) CO(g)+H2(g) →
Complete the following equations:
(i) PBS(s)+H2O2(aq) →
(ii) CO(g)+H2(g) →
This is a short answer type question as classified in NCERT Exemplar
(i) PBS (s)+4H2O2 (aq) → PbSO4 (s)+4H2O (l)
(ii) CO (g)+2H2 (g) → CH3OH (l)
Upvote 
For the reaction H2(g) + I2(g) ⇌ 2HI (g), the standard free energy is ∆Gᶱ > 0. The equilibrium constant (K ) would be __________.
(i) K = 0
(ii) K > 1
(iii) K = 1
(iv) K < 1
For the reaction H2(g) + I2(g) ⇌ 2HI (g), the standard free energy is ∆Gᶱ > 0. The equilibrium constant (K ) would be __________.
(i) K = 0
(ii) K > 1
(iii) K = 1
(iv) K < 1
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option(iv)
The given chemical reaction is:
H2(g) + I2(g) ? 2HI (g)
By, thermodynamical equation of equilibrium,
?G?= -RTlnk>0
Now, R>0 & T>0
⇒ −lnK > 0
⇒ K<1
Upvote We know that the relationship between Kc and Kp is
Kp = Kc (RT)∆n What would be the value of ∆n for the reaction
NH4Cl (s) ⇌ NH3 (g) + HCl (g)
(i) 1
(ii) 5
(iii) 5
(iv) 2
We know that the relationship between Kc and Kp is
Kp = Kc (RT)∆n What would be the value of ∆n for the reaction
NH4Cl (s) ⇌ NH3 (g) + HCl (g)
(i) 1
(ii) 5
(iii) 5
(iv) 2
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option(iv)
The relationship between Kp and Kc is
Kp=Kc(RT)Δn
Where ?n = (number of moles of gaseous products) – (number of moles of gaseous reactants)
For the reaction,
NH4C1(s)?NH3(g)+HCl(g)
Δn=2–0=2
Upvote Following data is given for the reaction: CaCO3 (s) → CaO (s) + CO2 (g)
∆fHᶱ [CaO(s)] = – 635.1 kJ mol–1
∆fHᶱ[CO2(g)] = – 393.5 kJ mol–1
∆fHᶱ[CaCO3(s)] = – 1206.9 kJ mol–1
Predict the effect of temperature on the equilibrium constant of the above reaction.
Following data is given for the reaction: CaCO3 (s) → CaO (s) + CO2 (g)
∆fHᶱ [CaO(s)] = – 635.1 kJ mol–1
∆fHᶱ[CO2(g)] = – 393.5 kJ mol–1
∆fHᶱ[CaCO3(s)] = – 1206.9 kJ mol–1
Predict the effect of temperature on the equilibrium constant of the above reaction.
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: ΔrH?= ?fH? [CaO(s)]+ ?fH?[CO2(g)]− ?fH?[ [CaCO3(s)]
∴ ?fH? =178.3kJ mol−1.
The reaction is endothermic. Hence, according to Le Chatelier’s principle, reaction will proceed in forward direction on increasing temperatur
Upvote If the same mass of liquid water and a piece of ice is taken, then why is the density of ice less than that of liquid water?
If the same mass of liquid water and a piece of ice is taken, then why is the density of ice less than that of liquid water?
This is a short answer type question as classified in NCERT Exemplar
Ice has a highly ordered 3D hydrogen bonded structure. Each oxygen atom is surrounded tetrahedrally by four other oxygen atoms at a distance of 276 pm.
Upvote A reaction between ammonia and boron trifluoride is given below: :
NH3 + BF3 → H3N : BF3 Identify the acid and base in this reaction. Which theory explains it? What is the hybridisation of B and N in the reactants?
A reaction between ammonia and boron trifluoride is given below: :
NH3 + BF3 → H3N : BF3 Identify the acid and base in this reaction. Which theory explains it? What is the hybridisation of B and N in the reactants?
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: As, NH3 is Lewis base while BF3 is Lewis acid. Lewis electronic theory of acids and bases explains it. Hybridisation state: N in NH3 is sp3 hybridised and Boron in BF3 is sp2 hybridised.
Upvote Calculate the volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution. (Ksp of PbCl2 = 3.2 × 10–8 , atomic mass of Pb = 207 u).
Calculate the volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution. (Ksp of PbCl2 = 3.2 × 10–8 , atomic mass of Pb = 207 u).
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans:
Ksp=3.2 × 10-8
PbCl2? Pb2+ +2Cl-
Ksp= (S) (2S)2
Ksp=4S3
s3=43.2 × 10-8
s3=8 × 10-9
s=2 × 10-3
Molar mass of PbCl2=278g/mol
By
Upvote The solubility product of Al(OH)3 is 2.7 × 10–11. Calculate its solubility in gL–1 and also find out pH of this solution. (Atomic mass of Al = 27 u).
The solubility product of Al(OH)3 is 2.7 × 10–11. Calculate its solubility in gL–1 and also find out pH of this solution. (Atomic mass of Al = 27 u).
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: Let us assume S be the solubility of Al (OH)3.
Ksp= [Al3+] [OH-]3= (S) (3S)3=27S4
S4=27Ksp=27 × 1027 × 10-11=1 × 10-12
S=1×10−3 mol L-1.
(i) Solubility of Al (OH)3 ? : Molar
Upvote Calculate the pH of a solution formed by mixing equal volumes of two solutions A and B of a strong acid having pH = 6 and pH = 4 respectively
Calculate the pH of a solution formed by mixing equal volumes of two solutions A and B of a strong acid having pH = 6 and pH = 4 respectively
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: we can find the pH of the solution as-
pH of solution A=6
Hence, concentration of [H+] ion in solution A=10-6mol L-1
pH of solution B=4
Therefore, concentration of [H]+ ion in solution&nbs
Upvote Name the classes of hydrides to which H2O, B2H6 and NaH belong.
Name the classes of hydrides to which H2O, B2H6 and NaH belong.
This is a short answer type question as classified in NCERT Exemplar
NaH belongs to Saline hydrides and B2H6 and H2O belong to molecular hydrides.
Upvote