Ncert Solutions Chemistry Class 11th
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Match the items given in Column I with examples given in Column II.
Column I
Column II
(i) Hydrogen bond
(a) C
(ii) Resonance
(b) LiF
(iii) Ionic solid
(c) H2
(iv) Covalent solid
(d) HF
(e) O3
Match the items given in Column I with examples given in Column II.
|
Column I |
Column II |
|
(i) Hydrogen bond |
(a) C |
|
(ii) Resonance |
(b) LiF |
|
(iii) Ionic solid |
(c) H2 |
|
(iv) Covalent solid |
(d) HF |
|
|
(e) O3 |
This is a Matching Type Questions as classified in NCERT Exemplar
Ans:
(i) Hydrogen bond (d) HF
(ii) Resonance (e
Upvote 
Match the species in Column I with the bond order in Column II.
Column I
Column II
(i) NO
1.5
(ii) CO
2.0
(iii) O22-
2.5
(iv) O2
3.0
Match the species in Column I with the bond order in Column II.
|
Column I |
Column II |
|
(i) NO |
1.5 |
|
(ii) CO |
2.0 |
|
(iii) O22- |
2.5 |
|
(iv) O2 |
3.0 |
This is a Matching Type Questions as classified in NCERT Exemplar
Ans:
(i) NO &n
Upvote Match the species in Column I with the geometry/shape in Column II.
Column I
Column II
(i) H3O+
(a) Linear
(ii) HC ≡ CH
(b) Angular
(iii) ClO2-
(c) Tetrahedral
(iv) NH4+
(d) Trigonal bipyramidal
(e) Pyramidal
Match the species in Column I with the geometry/shape in Column II.
|
Column I |
Column II |
|
(i) H3O+ |
(a) Linear |
|
(ii) HC ≡ CH |
(b) Angular |
|
(iii) ClO2- |
(c) Tetrahedral |
|
(iv) NH4+ |
(d) Trigonal bipyramidal |
|
|
(e) Pyramidal |
This is a Matching Type Questions as classified in NCERT Exemplar
Ans:
(i) H3O+
Upvote Match the species in Column I with the type of hybrid orbitals in Column II.
Match the species in Column I with the type of hybrid orbitals in Column II.
This is a Matching Type Questions as classified in NCERT Exemplar
Ans:
(i) SF4 (c) sp3d
(ii) IF5 (
Upvote Which of the following statements are not correct?
(i) NaCl being an ionic compound is a good conductor of electricity in the solid state.
(ii) In canonical structures there is a difference in the arrangement of atoms.
(iii) Hybrid orbitals form stronger bonds than pure orbitals.
(iv) VSEPR Theory can explain the square planar geometry of XeF4.
Which of the following statements are not correct?
(i) NaCl being an ionic compound is a good conductor of electricity in the solid state.
(ii) In canonical structures there is a difference in the arrangement of atoms.
(iii) Hybrid orbitals form stronger bonds than pure orbitals.
(iv) VSEPR Theory can explain the square planar geometry of XeF4.
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (i) and option (ii)
(i) NaCl being an ionic compound is a good conductor of electricity in the molten state. It is not a bad conductor of electricity in solid state. So, the statement mentioned in the question is not corr
Upvote Species having same bond order are :
(i) N2
(ii) N2–
(iii) F2+
(iv) O2–
Species having same bond order are :
(i) N2
(ii) N2–
(iii) F2+
(iv) O2–
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (iii) and (iv)
The formula of bond order is:
Bond order = ( Nb- Na)
Number of bonding and antibonding electrons can be found from the molecular electronic configuration of the species.
(i) Total number of electrons in N2 i
Upvote Dimagnetic species are those which contain no unpaired electrons. Which among the following are dimagnetic?
(i) N2
(ii) N22–
(iii) O2
(iv) O22-
Dimagnetic species are those which contain no unpaired electrons. Which among the following are dimagnetic?
(i) N2
(ii) N22–
(iii) O2
(iv) O22-
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (i) and (iv)
(i) N2 will have 14 electrons in its structure. So, its electronic configuration will be:
σ1s2 σ∗1s2 σ2s2 σ∗2s2, π2p2x , π2p2y, s2pz2
According to the molecular electronic configuration of N2 it does not contai
Upvote Which of the following statements are correct about CO32– ?
(i) The hybridisation of central atom is sp3.
(ii) Its resonance structure has one C–O single bond and two C=O double bonds.
(iii) The average formal charge on each oxygen atom is 0.67 units.
(iv) All C–O bond lengths are equal.
Which of the following statements are correct about CO32– ?
(i) The hybridisation of central atom is sp3.
(ii) Its resonance structure has one C–O single bond and two C=O double bonds.
(iii) The average formal charge on each oxygen atom is 0.67 units.
(iv) All C–O bond lengths are equal.
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (iii) and (iv)
(i) The hybridization of the central carbon atom in CO3 2- is 2 sp as the carbon is bonded with three oxygen atoms. So, the given statement is incorrect.
(ii) The resonance structure of CO32- has one C= O d
Upvote Which of the following species have the same shape?
(i) CO2
(ii) CCl4
(iii) O3
(iv) NO2-
Which of the following species have the same shape?
(i) CO2
(ii) CCl4
(iii) O3
(iv) NO2-
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (iii) and (iv)
(i) The number of valence electrons in CO2 is 14. The oxygen atom attached to the carbon atom forms a double bond. Therefore, the hybridization of the structure is sp2. Thus, carbon dioxide is linear in sha
Upvote CO is isoelectronic with
(i) NO+
(ii) N2
(iii) SnCl2
(iv) NO2-
CO is isoelectronic with
(i) NO+
(ii) N2
(iii) SnCl2
(iv) NO2-
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (i) and (ii)
The species having the same number of electrons are known as isoelectronic species.
The number of electrons in CO species is 14; 8 electrons from oxygen atom and 6 electrons from carbon atom.
The number of elect
Upvote