Ncert Solutions Chemistry Class 11th
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On the basis of Le Chatelier principle explain how temperature and pressure can be adjusted to increase the yield of ammonia in the following reaction.
N2(g) + 3H2(g) ⇌ 2NH3(g) ∆H = – 92.38 kJ mol–1
What will be the effect of addition of argon to the above reaction mixture at constant volume?
On the basis of Le Chatelier principle explain how temperature and pressure can be adjusted to increase the yield of ammonia in the following reaction.
N2(g) + 3H2(g) ⇌ 2NH3(g) ∆H = – 92.38 kJ mol–1
What will be the effect of addition of argon to the above reaction mixture at constant volume?
This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans: According to Le Chatelier's principle, when we raise the temperature, it shifts the equilibrium to left and decreases the equilibrium concentration of ammonia since it is an exothermic reaction. In other words, low temperature
How can you predict the following stages of a reaction by comparing the value of Kc and Qc ?
(i) Net reaction proceeds in the forward direction
(ii) Net reaction proceeds in the backward direction.
(iii) No net reaction occurs.
How can you predict the following stages of a reaction by comparing the value of Kc and Qc ?
(i) Net reaction proceeds in the forward direction
(ii) Net reaction proceeds in the backward direction.
(iii) No net reaction occurs.
This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans: The values of Kc and Qc are itself sufficient to explain the direction of reaction and less than or greater than one another decides the direction in which reaction will proceed as follows-
(i) As Qc < Kc, the reaction proceeds in the forward direction.
(ii) If Qc > Kc, the react
How will you concentrate H2O2? Show differences between structures of H2O2 and H2O by drawing their spatial structures. Also mention three important uses of H2O2.
How will you concentrate H2O2? Show differences between structures of H2O2 and H2O by drawing their spatial structures. Also mention three important uses of H2O2.
This is a long answer type question as classified in NCERT Exemplar
Hydrogen peroxide is produced by acidifying barium peroxide and eliminating surplus water by evaporation under low pressure. Water is used to extract it, then distillation under lower pressure concentrates it to around 30% (by mass).
How can D2O be prepared from water? Mention the physical properties in which D2O differs from H2O. Give at least three reactions of D2O showing the exchange of hydrogen with deuterium.
How can D2O be prepared from water? Mention the physical properties in which D2O differs from H2O. Give at least three reactions of D2O showing the exchange of hydrogen with deuterium.
This is a long answer type question as classified in NCERT Exemplar
D2O can be prepared by prolonged electrolysis of water. Due to high molecular mass D2O differs from water.
NaOH+D2O → NaOD+HOD
HCl+D2O → DCl+ HOD
NH4Cl+D2O → NH3DCl+HOD
Physical Properties of H2O and D2O
Property | H2O | D2O |
Molecular mass (g mol-1) | 18.015 | 20.0276 |
Melting point/K | 273.0 | 276.8 |
Boiling point/K | 373.0 | 374.4 |
Enthalpy of formation/kJ mol-1 | -285.9 | -294.6 |
Enthalpy of Vaporisation (373 K)/kJ mol-1 | 40.66 | 41.61 |
Enthalpy of fusion/kJ mol-1 | 6.01 | — |
Temp of max. density/K | 276.98 | 284.2 |
Density (298 K)/g cm-3 | 1.0000 | 1.1059 |
Viscosity/centipoise | 0.8903 | 1.107 |
Dielectric constant | 78.39 | 78.06 |
Atomic hydrogen combines with almost all elements but molecular hydrogen does not. Explain.
Atomic hydrogen combines with almost all elements but molecular hydrogen does not. Explain.
This is a long answer type question as classified in NCERT Exemplar
Atomic hydrogen is highly reactive, whereas molecular hydrogen is rather inert. Bond dissociation enthalpy determines the chemical behaviour of dihydrogen (and, for that matter, any molecule) to a great extent. For a single bond betw
Atomic hydrogen combines with almost all elements but molecular hydrogen does not. Explain.
Atomic hydrogen combines with almost all elements but molecular hydrogen does not. Explain.
This is a long answer type question as classified in NCERT Exemplar
Atomic hydrogen is highly reactive, whereas molecular hydrogen is rather inert. Bond dissociation enthalpy determines the chemical behaviour of dihydrogen (and, for that matter, any molecule) to a great extent. For a single bond betw
Assertion (A): Among the two O–H bonds in H2O molecule, the energy required to break the first O–H bond and the other O–H bond is the same.
Reason (R) : This is because the electronic environment around oxygen is the same even after breakage of one O–H bond.
(i) A and R both are correct, and R is correct explanation of A.
(ii) A and R both are correct, but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A and R both are false.
Assertion (A): Among the two O–H bonds in H2O molecule, the energy required to break the first O–H bond and the other O–H bond is the same.
Reason (R) : This is because the electronic environment around oxygen is the same even after breakage of one O–H bond.
(i) A and R both are correct, and R is correct explanation of A.
(ii) A and R both are correct, but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A and R both are false.
This is a Assertion Type Questions as classified in NCERT Exemplar
Ans: Option (iv)
Both the statements given in the assertion and reason are false.
The energy required to break the first O-H bond is not same than that of the second O-H bond in water molecule, that means the bond enthalpies of the two
Assertion (A) : Though the central atom of both NH3 and H2O molecules are sp3 hybridised, yet H–N–H bond angle is greater than that of H–O–H.
Reason (R) : This is because nitrogen atom has one lone pair and oxygen atom has two lone pairs.
(i) A and R both are correct, and R is the correct explanation of A.
(ii) A and R both are correct, but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A and R both are false.
Assertion (A) : Though the central atom of both NH3 and H2O molecules are sp3 hybridised, yet H–N–H bond angle is greater than that of H–O–H.
Reason (R) : This is because nitrogen atom has one lone pair and oxygen atom has two lone pairs.
(i) A and R both are correct, and R is the correct explanation of A.
(ii) A and R both are correct, but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A and R both are false.
This is a Assertion Type Questions as classified in NCERT Exemplar
Ans: Option (i)
The statements given in the assertion and reason, both are correct and the reason given is the correct explanation for the assertion. In NH3 only one lone pair of electron is present and due to that lone pair-bond pair
Assertion (A) : Sodium chloride formed by the action of chlorine gas on sodium metal is a stable compound.
Reason (R) : This is because sodium and chloride ions acquire octet in sodium chloride formation.
(i) A and R both are correct, and R is the correct explanation of A.
(ii) A and R both are correct, but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A and R both are false
Assertion (A) : Sodium chloride formed by the action of chlorine gas on sodium metal is a stable compound.
Reason (R) : This is because sodium and chloride ions acquire octet in sodium chloride formation.
(i) A and R both are correct, and R is the correct explanation of A.
(ii) A and R both are correct, but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A and R both are false
This is a Assertion Type Questions as classified in NCERT Exemplar
Ans: Option (i)
Both the statements given in assertion and reason are correct and the reason given is the correct explanation for the assertion. The sodium chloride formed by the action of chlorine gas on the sodium metal has a c
Match the shape of molecules in Column I with the type of hybridisation in Column II.
Column I
Column II
(i) Tetrahedral
(a) sp2
(ii) Trigonal
(b) sp
(iii) Linear
(c) sp3
Match the shape of molecules in Column I with the type of hybridisation in Column II.
|
Column I |
Column II |
|
(i) Tetrahedral |
(a) sp2 |
|
(ii) Trigonal |
(b) sp |
|
(iii) Linear |
(c) sp3 |
This is a Matching Type Questions as classified in NCERT Exemplar
Ans:
(i) Tetrahedral (c) sp3
(ii) Trigonal (a) sp2
(iii) Linear (b)sp
Explanation :-
(i) A tetrahedral molecule has four electron pairs and these make sigma bonds with each other. The s and p