NIT Rourkela - National Institute of Technology Cut-off
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New answer posted
4 months agoContributor-Level 10
For the General AI category, the competition has been decreasing from 2024 to 2026 (in the first round). For the OBC AI category, competition from 2024 to 2026 has also decreased.
For all the other All India categories, like SC, ST, EWS and PWD, the cutoff has been fluctuating. See below to know the cutoff in detail for the AI quota. Please note that other categories will have different cutoff trends.
| BTech CSE cutoff 2026 | BTech CSE cutoff 2025 | BTech CSE cutoff 2024 |
|---|---|---|
| General | ||
| 3606 | 3122 | 2680 |
| OBC | ||
| 1161 | 1011 | 968 |
| SC | ||
| 458 | 407 | 512 |
| ST | ||
| 216 | 230 | 193 |
| PWD | ||
| 94 | 96 | 40 |
| EWS | ||
| 515 | 338 | 396 |
New answer posted
4 months agoContributor-Level 10
To get admission at NIT Rourkela, General AI category students need to attain a rank of at least 41435 or below to be eligible, according to the round 1 of NIT Rourkela JEE Main cutoff 2026. For this category, the round 1 cutoff ranged from 398 to 41435. Among all the courses, BArch and Integrated BSc + MSc in Life Science were the most and least competitive courses for admission.
For the students who belong to the General HS category, the required round 1 rank needed for admission should be at least 61256 or below.
Please know that other categories, rounds, quotas, etc., will have different cutoffs. For more information, cli
New answer posted
4 months agoContributor-Level 10
NIT Rourkela CSE cutoff 2026 was 3606 for the General AI category in the first round. The NIT Rourkela JEE Main cutoff 2026 was published for the first round for admission to the BTech CSE and other courses.
See the table below to know the round 1 cutoff for both All India and Home State quota categories.
| Category | NIT Rourkela CSE cutoff 2026 |
|---|---|
| All India Quota Categories | |
| General | 3606 |
| OBC | 1161 |
| SC | 458 |
| ST | 216 |
| EWS | 515 |
| PWD | 94 |
| Home State Quota Categories | |
| General | 9635 |
| OBC | 4463 |
| SC | 1435 |
| ST | 1038 |
| EWS | 2177 |
| PWD | 108 |
New answer posted
a year agoContributor-Level 10
The highest rank to get into NIT Rourkela was 13474 for the OBC AI category in the first round. This cutoff was for the Integrated B.Sc. + M.Sc. in Life Science course. If you want admission to the BTech course, then the highest rank was 12025 for the BTech in Food Process Engineering course.
For the OBC HS category, the highest round 1 rank was 21229 for the Integrated BSc + MSc in Life Science course. In the BTech course branch, the highest rank was for the BTech in Ceramic Engineering + MTech in Industrial Ceramic Engineering course, with the cutoff being 19146.
The NIT Rourkela JEE Main cutoff 202
New answer posted
a year agoContributor-Level 10
NIT Rourkela JEE Main cutoff 2026 ranged from 398 to 41435 for the General AI category in the first round.
The NIT Rourkela cutoff 2026 was released for the first round for admission to the BTech, BArch, Integrated BSc+ MSc and BTech +MTech courses. See the table below to know the cutoff range for all AI and HS quota categories.
| Category (All India) | NIT Rourkela JEE Main cutoff 2026 |
|---|---|
| General | 398 - 41435 |
| OBC | 154- 13474 |
| SC | 60 - 6696 |
| ST | 22 - 2946 |
| PWD | 94 - 1163 |
| EWS | 115 - 6112 |
| Category (Home State) | NIT Rourkela JEE Main cutoff 2026 |
| General | 760 - 61256 |
| OBC | 703 - 21229 |
| SC | 250 - 12086 |
| ST | 41 - 5182 |
| PWD | 108 - 1978 |
| EWS | 144 -10329 |
New answer posted
2 years agoContributor-Level 10
NIT Rourkela MSc cutoff 2024 has been released across multiple specialisations. Based on the Round 1 seat allotment, the MSc cutoff score ranged between 132 and 1139 for the General AII India category students. Among all the MSc courses, M.Sc. in Life Science is the most competitive specialisation. So, considering the round 1 cutoff, candidates seeking admission to National Institute of Technology Rourkela must secure over and above the cutoff range mentioned here to be eligible.
A detailed course-wise NIT Rourkela CCMN cutoff 2024 is given below for the General category students under the AII India Quota. 
New answer posted
2 years agoContributor-Level 10
NIT Rourkela offers admission based on Joint Entrance Examination (JEE Main) and JoSAA counselling process. Since the official cutoff is not out yet, here is the tentative cutoff for the year 2024 :
• Computer Science and Engineering Opening Rank - 4494-4499
Closing Rank - 8282-8287
• Electrical Engineering
Opening Rank - 9943-9948
Closing Rank - 16085-16090
• Chemical Engineering
Opening Rank - 23595-23600
Closing Rank - 28064-28069
• Mechanical Engineering
Opening Rank - 16232-16237
New answer posted
2 years agoContributor-Level 10
A strong percentile in the target university and specialism is required for admission to NITs. In order to be considered for NIT seats, candidates typically need to have a percentile between 85 and 95. A strong percentile in the target university and specialism is required for admission to NITs. In order to be considered for NIT seats, candidates typically need to have a percentile between 85 and 95. JoSAA published the NIT Rourkela cutoff for the BTech and Integrated M.Tech programs. Other courses, such as MTech, require admission through the GATE cut-off. The results of the relevant entrance exam will be released along with the BTech
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