P Block Elements

Stannane is the tetrahedral shape of molecule.

Hybridisation is- sp³, shape and structure are tetrahedral

Number of replaceable H is 2.

$Pb{\left(N{O}_3\right)}_2\underset{673K}{\overset{\Delta }{\to }}PbO+\underset{\left(A\right)}{N{O}_2}+O_2$

$\underset{\left(A\right)}{N{O}_2}\underset{}{\overset{Dimerise}{\to }}\underset{\left(B\right)}{N_2{O}_4}$

Based upon the properties and uses of chemical substances.

P₄ + 3NaOH + 3H₂O ->  3NaH₂PO₂ + PH₃

(It's a disproportionation reaction)

(CH₃)₄Si is called silane, while CH₃Si (OH)₃ produced 2- dimensional silicone after the removal of water, similarity ${\left(C{H}_3\right)}_{2}Si{\left(OH\right)}_2$  produced chain form and ${\left(C{H}_3\right)}_{3}Si\left(OH\right)$  produced dimer form after releasing water molecules.

BaO₂ + H₂SO₄  BaSO₄ + H₂O₂

$6\mathrm{N}\mathrm{a}\mathrm{O}\mathrm{H}+3{\mathrm{C}\mathrm{l}}_2?5\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}+{\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}\mathrm{O}}_3+3{\mathrm{H}}_2\mathrm{O}$

$2\mathrm{C}\mathrm{a}(\mathrm{O}\mathrm{H}{)}_2+{\mathrm{C}\mathrm{l}}_2?\mathrm{C}\mathrm{a}(\mathrm{O}\mathrm{C}\mathrm{l}{)}_2+{\mathrm{C}\mathrm{a}\mathrm{C}\mathrm{l}}_2+{\mathrm{H}}_2\mathrm{O}$

$Xe{O}_3\Rightarrow s{p}^3,Pyramidal$

XeF₂ sp³d₂, square pyramidal

XeF₆ sp³d³, Distorted octahedral

XeOF₄ sp³d², square pyramidal

$S{O}_{2}C{l}_2+2H_{2}O\to H_{2}S{O}_4+2HCl$

Let a moles of SO2Cl2 is taken

Then no. of moles of H2SO4 = a moles

No. of moles of HCl = 2a moles

No. of moles of NaOH required = 2a + 2a = 4a = 16

$\Rightarrow a=4moles$