P Block Elements
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Which of the following options are not in accordance with the property mentioned against them?
(i) F2 > Cl2 > Br2 > I2 Oxidising power.
(ii) MI > MBr > MCl > MF Ionic character of metal halide.
(iii) F2 > Cl2 > Br2 > I2 Bond dissociation enthalpy.
(iv) HI < HBr < HCl < HF Hydrogen-halogen bond strength.
Which of the following options are not in accordance with the property mentioned against them?
(i) F2 > Cl2 > Br2 > I2 Oxidising power.
(ii) MI > MBr > MCl > MF Ionic character of metal halide.
(iii) F2 > Cl2 > Br2 > I2 Bond dissociation enthalpy.
(iv) HI < HBr < HCl < HF Hydrogen-halogen bond strength.
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (ii), (iii)
MI > MBr > MCl > MF is an iconic character of metal halide
F2 > Cl2 > Br2 > I2 is a bond dissociation enthalpy
Upvote 
If chlorine gas is passed through hot NaOH solution, two changes are observed in the oxidation number of chlorine during the reaction. These are ________ and _________.
(i) 0 to +5
(ii) 0 to +3
(iii) 0 to –1
(iv) 0 to +1
If chlorine gas is passed through hot NaOH solution, two changes are observed in the oxidation number of chlorine during the reaction. These are ________ and _________.
(i) 0 to +5
(ii) 0 to +3
(iii) 0 to –1
(iv) 0 to +1
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (i) and (iii)
6NaOH+3Cl2 → 5NaCl+NaClO3+3H2O
Chlorine gas oxidation number ranges from 0 to –1 to 0 to +5.
Upvote Which of the following is an isoelectronic pair?
(i) ICl2 , ClO2
(ii) BrO2- , BrF2
(iii) ClO2 , BrF
(iv) CN- , O3
Which of the following is an isoelectronic pair?
(i) ICl2 , ClO2
(ii) BrO2- , BrF2
(iii) ClO2 , BrF
(iv) CN- , O3
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (ii)
BrO2- (35+2×8+1=52) and BrF2+ (35+2×9−1=52)
52 electrons are present in both
Upvote Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.
(i) ClO4- > IO4- > BrO4-
(ii) IO4- > BrO4- > ClO4-
(iii) BrO4- > IO4- > ClO4-
(iv) BrO4- > ClO4- > IO4-
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.
(i) ClO4- > IO4- > BrO4-
(ii) IO4- > BrO4- > ClO4-
(iii) BrO4- > IO4- > ClO4-
(iv) BrO4- > ClO4- > IO4-
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iii)
The ability of a substance to be decreased is known as its reduction potential. As the substance's reduction potential rises, so does its power to reduce. It signifies the chemical's oxidising power (the ability o
Upvote In solid state PCl5 is a _________.
(i) Covalent solid
(ii) Octahedral structure
(iii) Ionic solid with [PCl6]+ octahedral and [PCl4]− tetrahedral
(iv) Ionic solid with [PCl4]+ tetrahedral and [PCl6]− octahedral
In solid state PCl5 is a _________.
(i) Covalent solid
(ii) Octahedral structure
(iii) Ionic solid with [PCl6]+ octahedral and [PCl4]− tetrahedral
(iv) Ionic solid with [PCl4]+ tetrahedral and [PCl6]− octahedral
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iv)
The ionic bonding promotes the crystalline structure of PCl5 in the solid state by attempting to exist as oppositely charged ions like [PCl4]+ and [PCl6]− . Also,
Upvote In the preparation of compounds of Xe, Bartlett had taken O2+ PtF6− as a base compound. This is because
(i) Both O2 and Xe have the same size.
(ii) Both O2 and Xe have the same electron gain enthalpy.
(iii) Both O2 and Xe have almost the same ionisation enthalpy.
(iv) Both O2 and Xe are gases.
In the preparation of compounds of Xe, Bartlett had taken O2+ PtF6− as a base compound. This is because
(i) Both O2 and Xe have the same size.
(ii) Both O2 and Xe have the same electron gain enthalpy.
(iii) Both O2 and Xe have almost the same ionisation enthalpy.
(iv) Both O2 and Xe are gases.
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iii)
Bartlett noticed that Xenon's first ionisation potential is nearly identical to that of oxygen and used Born-Haber calculations to predict the presence of a stable compound: Xe+ Pt F6-
Upvote A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When excess of this gas reacts with NH3 an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from _________.
(i) – 3 to +3
(ii) – 3 to 0
(iii) – 3 to +5
(iv) 0 to – 3
A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When excess of this gas reacts with NH3 an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from _________.
(i) – 3 to +3
(ii) – 3 to 0
(iii) – 3 to +5
(iv) 0 to – 3
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iv)
MnO2 ( Black )+4HCl→MnCl2+2H2O+Cl2
Greenish yellow color
Upvote Hot conc. H2SO4 acts as moderately strong oxidising agent. It oxidises both metals and nonmetals. Which of the following element is oxidised by conc. H2SO4 into two gaseous products?
(i) Cu
(ii) S
(iii) C
(iv) Zn
Hot conc. H2SO4 acts as moderately strong oxidising agent. It oxidises both metals and nonmetals. Which of the following element is oxidised by conc. H2SO4 into two gaseous products?
(i) Cu
(ii) S
(iii) C
(iv) Zn
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iii)
C+2H2SO4→CO2+2SO2+2H2O
Conc. H2SO4 oxidises C to produce two gaseous products.
Upvote Which of the following are peroxoacids of sulphur?
(i) H2SO5 and H2S2O8
(ii) H2SO5 and H2S2O7
(iii) H2S2O7 and H2S2O8
(iv) H2S2O6 and H2S2O7
Which of the following are peroxoacids of sulphur?
(i) H2SO5 and H2S2O8
(ii) H2SO5 and H2S2O7
(iii) H2S2O7 and H2S2O8
(iv) H2S2O6 and H2S2O7
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (i)
Peroxy linkage refers to the presence of a bond between oxygen and oxygen (O-O) in a molecule.
Only H2S2O6 and H2S2O7 of the sulphur oxoacids above have a peroxy linkage.
Upvote Which of the following is not tetrahedral in shape?
(i) NH4+
(ii) SiCl4
(iii) SF4
(iv) SO42−
Which of the following is not tetrahedral in shape?
(i) NH4+
(ii) SiCl4
(iii) SF4
(iv) SO42−
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iii)
The C-atom in the CO32- ion undergoes sp2 hybridization. BF4, NH4+ and SO42- have a tetrahedral structure, whereas it has a triangular planar structure.
Upvote