P Block Elements

(CH₃)₄Si is called silane, while CH₃Si (OH)₃ produced 2- dimensional silicone after the removal of water, similarity ${\left(C{H}_3\right)}_{2}Si{\left(OH\right)}_2$  produced chain form and ${\left(C{H}_3\right)}_{3}Si\left(OH\right)$  produced dimer form after releasing water molecules.

BaO₂ + H₂SO₄  BaSO₄ + H₂O₂

$6\mathrm{N}\mathrm{a}\mathrm{O}\mathrm{H}+3{\mathrm{C}\mathrm{l}}_2?5\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}+{\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}\mathrm{O}}_3+3{\mathrm{H}}_2\mathrm{O}$

$2\mathrm{C}\mathrm{a}(\mathrm{O}\mathrm{H}{)}_2+{\mathrm{C}\mathrm{l}}_2?\mathrm{C}\mathrm{a}(\mathrm{O}\mathrm{C}\mathrm{l}{)}_2+{\mathrm{C}\mathrm{a}\mathrm{C}\mathrm{l}}_2+{\mathrm{H}}_2\mathrm{O}$

$Xe{O}_3\Rightarrow s{p}^3,Pyramidal$

XeF₂ sp³d₂, square pyramidal

XeF₆ sp³d³, Distorted octahedral

XeOF₄ sp³d², square pyramidal

$S{O}_{2}C{l}_2+2H_{2}O\to H_{2}S{O}_4+2HCl$

Let a moles of SO2Cl2 is taken

Then no. of moles of H2SO4 = a moles

No. of moles of HCl = 2a moles

No. of moles of NaOH required = 2a + 2a = 4a = 16

$\Rightarrow a=4moles$

Pyrophosphorous acid = H₄P₂O₅

 Hypophosphorous acid = H₄P₂O₆

 Phosphoric acid = H₃PO₄

 Pyrophosphoric acid = H₄P₂O₇

Cobalt (II) meta borate is a blue colour of Bead.

Here 'X' is the Gypsum (CaSO₄.2H₂O) which is used to enhance the setting of time

Stannane is the tetrahedral shape of molecule.

Hybridisation is- sp³, shape and structure are tetrahedral

(a) Nitric oxide formation -> Pt is used as catalyst

(b) Haber's process -> Fe is used as catalyst

(c) Hydrolysis of ester -> Acid (H₂SO₄) is used as catalyst

(d) SO₃ formation -> NO is used as catalyst