P Block Elements

Strongest reducing agent among the following is

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Correct order of reducing character is

NH₃ < PH₃ < AsH₃ < SbH₃ < BiH₃

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Correct formula of calamine is

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Calamine -> ZnCO₃

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Shape of XeF₄ molecule is

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Hybridisation = sp³d²

Shape – square planar

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Anionic species obtained on reaction of XeF₂ with PF₅ is

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$X e F_{2} + P F_{5} \to {[X e F]}^{+} {[P F_{6}]}^{-}$

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The correct shape and hybridization for XeF2 are

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XeF2 : Hybrid orbital = sigma bond + L.P

= 2 + 3

= 5 = sp3d

Shape will be linear

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Which of the following is least likely to exist?

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HBrO2 has least existence

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In mildly alkaline medium, thiosulphate ion is oxidized by $M n O_{4}^{-}$ to “A”. The oxidation state of sulphur in 'A' is………….

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$M n O_{4}^{-} + S_{2} O_{3}^{2 -} \overset{O H^{-}}{\to} M n O_{2} + S O_{4}^{2 -}$

O.S of S in $S O_{4}^{2 -} = + 6$

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Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A : In TlI₃, isomorphous to CsI₃, the metal is present in +1 oxidation state.

Reason R : Tl metal has fourteen f electrons in the electronic configuration.

In the light of the above statements, choose the most appropriate answer from the options given below:

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Both (A) and (B) are correct but R is not correct explanation of A. In both oxidation state of metal is +1, also both have similar lattice structure.

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Match List – I and List – II.

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2 C H_{3} C H_{2} C l \to_{e t h e r}^{2 N a} C_{2} H_{5} - C_{2} H_{5} + 2 N a C l (W u r t z R e a c t i o n)

2 C_{6} H_{5} C l \to_{e t h e r}^{2 N a} C_{6} H_{5} - C_{6} H_{5} + 2 N a C l (W i t t i n g R e a c t i o n)

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Consider the following reaction:

A + alkali -> B(Major Product)

If B is an oxoacid of phosphorous with no P-H bond, then A is:

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