P Block Elements
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The molar conductivity of 0.007M acetic acid is 20 S² mol⁻¹. What is the dissociation constant of acetic acid? Choose the correct option.
[Λ°(H⁺) = 350 Scm² mol⁻¹]
[Λ°(CH₃COO⁻) = 50 Scm² mol⁻¹]
The molar conductivity of 0.007M acetic acid is 20 S² mol⁻¹. What is the dissociation constant of acetic acid? Choose the correct option.
[Λ°(H⁺) = 350 Scm² mol⁻¹]
[Λ°(CH₃COO⁻) = 50 Scm² mol⁻¹]
Λ°? (CH? COOH) = Λ°? (H? ) + Λ°? (CH? COO? ) = 350 + 50 = 400Scm² mol? ¹
α = Λ? / Λ°?
α = 20/400 = 5 × 10? ²
K? (CH? COOH) = Cα²
= 0.007 × (5 × 10? ²)²
= 1.75 × 10? molL? ¹
The RBC deficiency is deficiency disease of :
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The RBC deficiency is deficiency disease of :
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Vitamin B? deficiency → Pernicious anaemia (RBC deficient in heamoglobin)
In the neutral or faintly alkaline medium, KMnO4 oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from:
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In the neutral or faintly alkaline medium, KMnO4 oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from:
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Oxidation state in neutral medium changes from +7 to +4 for MnO? to MnO?
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): ICl is more reactive than I?.
Reason (R): I-Cl bond is weaker than I-I bond.
In the light of the above statements, choose the most appropriate answer from the options given below:
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): ICl is more reactive than I?.
Reason (R): I-Cl bond is weaker than I-I bond.
In the light of the above statements, choose the most appropriate answer from the options given below:
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I - Cl bond is stronger than I-I bond due to additional electrostatic force between I and Cl.
The solubility of CdSO? in water is 8.0 × 10? mol L?¹. Its solubility in 0.01 M H?SO? solution is ________ × 10? mol L?¹. (Round off to the nearest integer).
(Assume that solubility is much less than 0.01 M)
The solubility of CdSO? in water is 8.0 × 10? mol L?¹. Its solubility in 0.01 M H?SO? solution is ________ × 10? mol L?¹. (Round off to the nearest integer).
(Assume that solubility is much less than 0.01 M)
Solubility of CdSO? is water ; S = 8 × 10? M
Using Ksp = S²
Ksp = 64 × 10? M
Now,
CdSO? Cd²? + SO? ²?
in H? SO? (0.01M)
Ksp = [Cd²? ] [SO? ²? ]
64 × 10? = S? (S? + 0.01)
S? << 0.01
So, S? = 64 × 10? M.
A xenon compound 'A' upon partial hydrolysis gives XeO?F?. The number of lone pair of electrons present in compound A is ________. (Round off to the nearest integer).
A xenon compound 'A' upon partial hydrolysis gives XeO?F?. The number of lone pair of electrons present in compound A is ________. (Round off to the nearest integer).
Partial hydrolysis of XeF? gives XeO? F?
XeF? + 2H? O → XeO? F? + 4HF
Compound A is XeF? , so number of lone pair on Xe is 1.
The INCORRECT statement regarding the structure of C₆₀ is:
The INCORRECT statement regarding the structure of C₆₀ is:
In a C? fullerene molecule, all 60 carbon atoms are identical. Each carbon atom is bonded to three other carbon atoms via sigma bonds. The structure is composed of 20 six-membered rings and 12 five-membered rings.
Match List – I with List – II:
List – I List – II
(a) [Co(NH3)6][Cr(CN)6] (i) Linkage isomerism
(b) [Co(NH3)3(NO2)3] (ii) Solvate isomerism
(c) [Cr(H2O)6]Cl3 (iii) Co-ordination isomerism
(d) cis - [CrCl2(ox)2]³? (iv) Optical isomerism
Choose the correct answer from the options given below:
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Match List – I with List – II:
List – I List – II
(a) [Co(NH3)6][Cr(CN)6] (i) Linkage isomerism
(b) [Co(NH3)3(NO2)3] (ii) Solvate isomerism
(c) [Cr(H2O)6]Cl3 (iii) Co-ordination isomerism
(d) cis - [CrCl2(ox)2]³? (iv) Optical isomerism
Choose the correct answer from the options given below:
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Co (NH? )? ] [Cr (CN)? ]: Co-ordination isomerism
[Co (NH? )? (NO? )? ]: Linkage isomerism
[Cr (H? O)? ]Cl? : Solvate isomerism
Cis- [CrCl? (Ox)? ]³? : Optical isomerism
The reaction of white phosphorous on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction of 1 mol of 'A' with excess of AgNO₃ in aqueous medium gives _______ mol(s) of Ag. (Round off to the nearest integer).
The reaction of white phosphorous on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction of 1 mol of 'A' with excess of AgNO₃ in aqueous medium gives _______ mol(s) of Ag. (Round off to the nearest integer).
P? + 3NaOH + 3H? O → PH? + 3NaH? PO? (A)
Here, NaH? PO? is a reducing agent.
NaH? PO? + AgNO? + H? O → Ag + HNO? + NaH? PO?
Equivalents of NaH? PO? = equivalents of Ag (n-factor of NaH? PO? = 4)
1 mole × 4 = n moles of Ag × 1
So, moles of Ag = 4.
The incorrect statement(s) among (a) - (c) is (are):
(a) W(VI) is more stable than Cr(VI).
(b) in the presence of HCl, permanganate titrations provide satisfactory results.
(c) some lanthanoid oxides can be used as phosphors.
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The incorrect statement(s) among (a) - (c) is (are):
(a) W(VI) is more stable than Cr(VI).
(b) in the presence of HCl, permanganate titrations provide satisfactory results.
(c) some lanthanoid oxides can be used as phosphors.
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