Physics Electrostatic Potential and Capacitance

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V
Vishal Baghel

Contributor-Level 10

λ = c v = Q 3 W 2 = I 3 T 3 M 2 L 4 T 4 [ λ ] = [ M 2 L 4 T 7 l 3 ]                                                                             

 

 

 

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

According question, we can write

C1*C2C1+C2=154 (C1+C2)4C1C2=15 (C12+C22+2C1C2)

4 (C2C1)=15 (C2C1)2+30 (C2C1)+1515x2+26x+15=0,  where x = C2C1

x=26±67690030

Since x cannot be real, so this Question has been dropped by NTA

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

After contact, charges an each sphere will be

q1+q22=1ncF=kq1q2r2=36*109N

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P
Payal Gupta

Contributor-Level 10

Tsinθ=kq2r2

Tcosθ=mg

tanθ=kq2mgr2

Using the above equation find the value of 'q'

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a month ago

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A
alok kumar singh

Contributor-Level 10

Given  V = V = Constant

 (i) C = ε 0 A d , C = ε 0 A d

d < d

C > C
Hence, final capacitance greater than initial capacitance,

(ii)  U = 1 2 C V 2

U = 1 2 C V 2

U > U

Hence final energy is greater than initial energy

(iii)  Q V = C and Q V = C

Q V Q V

(iv) Product of charge and voltage

X = Q V = C V 2

X = Q V = C V 2

X > X

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a month ago

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A
alok kumar singh

Contributor-Level 10

For uniformly charged spherical shell,

V = k q R (  For rR )

V C = V P

VCVP= Zero 

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

(A) If c  is the velocity of light

so,   E = h ν   (Energy of photon)

(B) Velocity of photon is equal to velocity of light i.e. c.

(C)  λ = h p

p = h λ

p = h v c

(D) In photon-electron collision both total energy and total momentum are conserved.

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a month ago

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A
alok kumar singh

Contributor-Level 10

V . C = M S D V S D     … (i)

given :  (N+1)VSD=NMSD

VSD= (NN+1)MSD     … (ii)

From (1) and (2)

V . C = ( MSD ) N N + 1 ( MSD )

=MSD (1NN+1)=MSDN+1

= 0 . 0 1 N + 1 = 1 1 0 0 ( N + 1 )

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a month ago

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P
Payal Gupta

Contributor-Level 10

Capacitance of each capacitor

C1=A3ε012=6Aε0

C2=A4ε0=4Aε0

Equivalent capacitance

Δv2=240Aε04Aε0=60v

vfoil=60v

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a month ago

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A
alok kumar singh

Contributor-Level 10

The potential V at any point, at distance r from centre of dipole = KPcosθ r 2

At axial point where  θ=0? , V=KPr2=9*109*4*10622=9*103 V

At axial point where  θ=180? , V=KPr2=9*103 V

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