Physics

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New answer posted

a year ago

0 Follower 8 Views

P
Pallavi Pathak

Contributor-Level 10

In NEET entrance test, the weightage of Class 11 Physics Chapter 11 Thermodynamics is around 7%. Students should thoroughly understand the thermodynamic laws and internal energy. The medical entrance test includes theory and numerically-based questions. For JEE Main, the chapter has more significance, and it has nearly 15% weightage of the total Physics syllabus.

New answer posted

a year ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

W A B = n R T l n 2 V 1 V 1 = n R T l n 2 .

W B C = P 2 ( V 1 − 2 V 1 ) = − P 2 V 1 = − 1 2 n R T                         

[At B, 2P2 V1 = nRT]

W C A = 0   [CA is isochoric process].

W A B C A = W A B + W B C + W C A = n R T ( l n ( 2 ) − 1 2 )            

New answer posted

a year ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Given, L = 2H

l = 2 sin (t2)

u = ∫ 0 2 L i d i = L 2 [ i 2 ] 0 2 = L 2 [ 4 − 0 ]

u = 2 2 * 4 = 4 J

New answer posted

a year ago

0 Follower 4 Views

A
Aadit Singh Uppal

Contributor-Level 10

Power calculations can also differ based on the nature of forces, which are as follows:

  • Conservative Forces: Here, work done is path-independent. e.g., gravity, spring force
  • Non-Conservative Forces: Work depends on the path. e.g., friction

New answer posted

a year ago

0 Follower 74 Views

R
Raj Pandey

Contributor-Level 9

≡ R e q = 2 . 5 Ω

l = v R e q = 5 2 . 5 = 2 A

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

l 1 = 1 2 m r 2

l 2 = 1 2 m r 2 l 3 = 1 2 m r 2 l 4 = 2 5 m r 2

New question posted

a year ago

0 Follower 3 Views

New answer posted

a year ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

H = I 2 R t = 2 2 * R * 1 5

⇒ 3 0 0 = 6 0 R

R = 5 Ω

Now for 3A, time = 10 sec

H ' = l 2 R t = 3 2 * 5 * 1 0 = 4 5 0 J

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

m ω 2 . 2 d 3 = G . m . 2 m d 2 ⇒ ω = 3 G m d 3

T = 2 π ω = 2 π d 3 3 G m

 

New answer posted

a year ago

0 Follower 18 Views

R
Raj Pandey

Contributor-Level 9

ceq = 2 4 * 8 3 2 = 6 μ F

 

 

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