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New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

When connected in series, equivalent capacitance,

C 1 = C * C C + C = C 2            

When connected in parallel, equivalent capacitance

C2 = C + C = 2C

C 1 C 2 = C / 2 2 C = 1 4            

New answer posted

10 months ago

0 Follower 12 Views

A
alok kumar singh

Contributor-Level 10

i = 6 4 2 + 8 = 0 . 2 A

V x + 4 + 0 . 2 * 8 = V Y

V Y V X = 5 . 6 V

 

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

p = h λ  

So, two photons having equal linear momenta have equal wavelength. As wavelength decreases, momentum and energy of photon increases.

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

  ω = 2 π T ω 1 ω 2 = T 2 T 1 = 8

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

  v = 1 ε μ = 1 2 ε 0 . 2 μ 0 = 1 2 ε 0 μ 0 = c 2 = 1 5 * 1 0 7 m / s .

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

  N p N s = V p V s N p = V p V s * N s = 2 2 0 1 2 * 2 4 = 4 4 0

New answer posted

10 months ago

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alok kumar singh

Contributor-Level 10

l = l 0 c o s 2 θ = 1 0 0 * c o s 2 ( 3 0 ° ) = 7 5 L u m e n s

Note : As the incident light is unpolarized, intensity of emerging light does not depend on the polarization axis of polarizer.

New answer posted

10 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

If the block does not slide,

mg sin    θ μ m g c o s θ

  t a n θ μ d y d x μ x 2 0 . 5 x 1 m .          

Thus, y 1 2 4 = 0 . 2 5 m = 2 5 c m .

 

New answer posted

10 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Using conversation of momentum in direction perpendicular to the original direction of motion,

mv1 sin 30° = mv2 sin 30°

 

 

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Quality factor =   ω L R = 2 * 3 . 1 4 * 1 0 * 1 0 6 * 2 * 1 0 4 6 . 2 8 = 2 0 0 0

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