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New question posted
10 months agoNew answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (a)
Explanation- R= for greater value of R, A should be less and its possible value when connected across 1cm 1/2cm faces.
New answer posted
10 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
molar mass = mass of avogadro's number of atoms= 6.023 atoms.
197 g of gold contains =6.023
1g of gold contain= atoms
39.4 g of gold atoms = atoms
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (b)
Explanation-The potential drop along the wires of potentiometer should be greater than emfs of cells.
In a potentiometer experiment, the emf of a cell can be measured if the potential drop along the potentiometer wire is more than the emf of the cell to be determined. Here, values of emfs of two cells are given as 5 V and 10 V, therefore, the potential drop along the potentiometer wire must be more than 10 V.
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer – (c)
Explanation – R/S= (l1/100-l1)= 100 (2.9/100-2.9)= 100/97.1=2.98ohm
So he should change S to almost 3 ohm and repeat the experiment.
New answer posted
10 months agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
Consider the diagram

let n =number of molecules per unit volume
Vrms= rms speed of gas molecule
When block is moving with speed vo, relative speed of molecules w.r.t front face =v+vo
Coming head on, momentum transferred to block per collision =2m (v+vo)
Number of collisions in time = (v+vo)n A where A is the area of cross section.
So momentum transferred in time =m (v+vo)2nA this is from front surface
Similarly momentum transferred in time = m (v-vo)2nA ) this is from back surface
Drag force = mnA (v+vo)2- (v-vo)2)
= mnA (4wo)=4mnAvvo
= 4 vvo
So =mn/V=M/
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (a)
Explanation- eeq=
New answer posted
10 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (b)
Explanation- as we know that J=E, and current density is directly proportional to electric field, so electric field produced by charges accumulated on the surface of wire.
New answer posted
10 months agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
Given volume V = 1m3
area = 0.01mm2

= 8.01 m2= m2
Temperature both inside and outside are equal
So initial pressure inside the box = 1.50atm
Final pressure inside the box= 0.1atm
Assuming Vx= speed of nitrogen molecule in x direction
ni = number of molecules per unit volume in a time interval of
Let area of the wall, number of particles colliding in time
= i (vx )A , here we use ½ because particle moves both in positive and negative direction.
Vx2+ Vy2+ Vz2= Vrms2
Vx2= Vrms2/3 if all three velocities are equal.
½ mvrms2= 3/2KBT/m


New answer posted
10 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
Explanation- according to ohms law
I=

If voltage and resistance increase
V'= nVeff, R'= nReff
I'= =
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