Quantitative Aptitude Prep Tips for MBA
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New answer posted
a month agoContributor-Level 10
CI7 – CI6 = 1450 – 1250
= Rs. 200
Rate of interest = (200/1250*100)
=16% per annum
New answer posted
a month agoContributor-Level 10
Difference between the speed = 90 km/hr
= 90*5/18 = 25 m/s
Time taken = (640 + 480)/25
= 44.8 seconds
New answer posted
a month agoContributor-Level 10
Sum of length = (72*5/18)*73
=1460 m
Length of platform = 1460 – 422
= 1040 m
New answer posted
a month agoContributor-Level 10
Speed of A with respect to B
AB = 36 – 24 = 12 km/hr
Time taken by A to catch B
AB = 120/12 = 10 hours
New answer posted
a month agoContributor-Level 10
Let total work is 60 (LCM of 20, 12 & 15)
Per day work
(Raj + Mohan) = 3 units
(Mohan + Sohan) = 5 units
(Raj + Shohan) = 4 units
(Raj + Mohan + Sohan) = (3 + 5 + 4)/2 = 6 units
Raj's per day work = 6 – 5 = 1 unit
Total time taken by Raj = 60 days
New answer posted
a month agoContributor-Level 10
Total days taken by Mahesh alone = 45*4 = 180 days
Let the total work = 180 units (LCM of 180 and 60)
Mahesh per day work = 1 units
Mahesh and Anand per day work = 180/60 = 3 units
Anand per day work = 3 – 1 = 2
Time taken = 180/2 = 90 days
New answer posted
a month agoContributor-Level 10
Food for 80 person = 150 days
Food for 1 person = 150 * 80
Food for 150 person = (150 * 80/150)
= 80 days
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