Semiconductor Electronics: Materials, Devices and

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New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

ni² = ne * nh
(1.5*10¹? )² = ne * (4.5*10²²)
ne = (2.25 * 10³²)/ (4.5 * 10²²) = 0.5 * 10¹? = 5 * 10? / m³

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

As we know, β = Ic/Ib = 24 (Given)
R = 1000Ω, ΔV = 0.6V, Ic = ΔV/R = 0.6/1000 = 6*10? A
So, Ib = Ic/β = (6*10? )/24 = 25*10? A
or Ib = 25µA

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

l = 9 0 3 0 4 0 0 0 = 1 5 m A

I 1 = 3 0 5 0 0 0 = 6 m A & l 2 = 9 m A

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

y = A ¯ + B ¯ = A . B ¯

 

 

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

D1 is forward biased & D2 is reverse biased.

l=6120+130+50=6300=2*102A=20*103A=20mA

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

λ=hcE=6.63*1034*3*1081.9*1.6*1019 = 654 nm (red)

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a month ago

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V
Vishal Baghel

Contributor-Level 10

A tristor is formed by doping a semi conductor water from one side by N-type dopant (high concentration while comparatively lower concentration on other side thus forming NPN tristor & vice-versa.

So, statement (I) is false & statement (II) is true.

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

Zener break down occurs in p-n junction having p and n both : Heavily doped and have narrow depletion layer.

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

D1 is in forward bias and D2 is in reverse bias.

Current, I = 5 0 . 7 1 0 = 0 . 4 3 A

New question posted

a month ago

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