Semiconductor Electronics: Materials, Devices and

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New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

Zener break down occurs in p-n junction having p and n both : Heavily doped and have narrow depletion layer.

New answer posted

4 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

D1 is in forward bias and D2 is in reverse bias.

Current, I = 5 0 . 7 1 0 = 0 . 4 3 A

New question posted

4 months ago

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New answer posted

4 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Fermi level of p-type semiconductors will go downward

New answer posted

4 months ago

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P
Payal Gupta

Contributor-Level 10

Using truth table of logic gates

Y= (AB¯)+ (A¯B)¯= ( (AB¯))¯ ( (A¯B))¯

Y= (A¯+B¯) (A¯+B¯)= (A¯+B) (A+B¯)=AB+A¯B¯

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Y 1 = A · A ¯

= A ¯

Y 2 = B + B ¯

= B ¯

Y = Y 1 + Y 2 ¯

= A ¯ + B ¯ ¯

= A ¯ ¯ · B ¯ ¯

=A·B is similar to output of AND Gate 

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

According to transformer ratio,

V S V P = N S N P = 2 : 1

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5 months ago

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P
Payal Gupta

Contributor-Level 10

l=120604000=0.015A

Thus l2 = l - LL

= 0.015 – 0.006

= 0.009 = 9mA

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

For 90 mA in zener diode, current in R should be greater than 90 mA.

4 5 R = 9 0 * 1 0 3 R = 4 5 9 0 * 1 0 3 = 5 0 0 Ω

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

E = h c λ = 1 2 4 2 e V n m 6 2 1 n m = 2 e V

minimum 2eV is required to emit.

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