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Semiconductor Electronics: Materials, Devices and

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Semiconductor Electronics: Materials, Devices and Class 12th

Statement-I : To get a steady dc output from the pulsating voltage received from a full wave rectifier we can connect a capacitor across the output parallel to the load RL.

Statement-II : To get a steady dc output from the pulsating voltage received from a full wave rectifier we can connect an inductor in series with RL.

In the light of the above statements, choose the most appropriate answer from the options given below:

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Vishal Baghel

Contributor-Level 10

Capacitor makes potential difference constant.

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Semiconductor Electronics: Materials, Devices and Class 12th

If VA and VB are the input voltages (either 5V or 0V) and Vo is the output voltage then the two gates represented in the following circuit (A) and (B) are:-

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Vishal Baghel

Contributor-Level 10

Using truth table

A B V₀

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0 1 1

1 0 1

1 1

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Semiconductor Electronics: Materials, Devices and Class 12th

In the given figure, each diode has a forward bias resistance of 30 $Ω$ and infinite resistance in reverse bias. The current I₁ will be:

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alok kumar singh

Contributor-Level 10

In give diagram Diode 1 and 2 are in forward bias with R = $30 Ω$ and Diode 3 is reverse bias with R = infinite l₁ current is flowing through 20 $Ω$

So $\frac{l_{1}}{2} a n d \frac{l_{1}}{2}$ current will flow through Diode 1 and 2. As resistance is same applying KCl in ABCD Loop $- \frac{l_{1}}{2} * 130 - \frac{l_{1}}{2} * 130 - l_{1} * 20 + 200 = 0$

-100l₁ + 200 = 0

l₁ = 2

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2 months ago

Semiconductor Electronics: Materials, Devices and Class 12th

Consider a galvanometer shunted with 5 $Ω$ resistance and 2% of current passes through it. What is the resistance of the given galvanometer?

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Raj Pandey

Contributor-Level 9

0.02i * R_G = 0.98i * 5

[in parallel, pot. Diff is same]

or, R_G = 49 * 5

R_G = 245 $Ω$

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2 months ago

Semiconductor Electronics: Materials, Devices and Class 12th

A zener diode of power rating 2W is to be used as a voltage regulator. If the zener diode ha s breakdown of 40V and its has to regulate voltage fluctuated between 6 V and 14 V, the value of R_s for safe operation should be_______ $Ω .$

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alok kumar singh

Contributor-Level 10

Maximum current through zener diode,

$i = \frac{2}{10} = 0.2 A$

When unregulated voltage is 14V,

Potential difference across Rs,

V_S = 14 – 10 = 4V

$R_{S} = \frac{V_{S}}{i} = \frac{4}{0.2} = 20 Ω$

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Semiconductor Electronics: Materials, Devices and Class 12th

The voltage drop across $15 Ω$ resistance in the given figure will be_______V.

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Semiconductor Electronics: Materials, Devices and Class 12th

For a transistor a and b are given as $α = \frac{I_{C}}{I_{E}} a n d β = \frac{I_{C}}{I_{B}} .$ Then the correct relation between a and b will be: