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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(i) Kkg mol–1 or K (molality)-1

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Payal Gupta

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(ii) 1.0 M Na2SO4

Explanation: When compared to the other three electrolytes, the van't Hoff factor in 1.0 M Na2SO4 solution is I > 1 and is the highest. As a result, when compared to the other electrolytes in their 1.0 M solutions, the extent of dissociation in the case of 1.0 M Na2SO4 would be the greatest, giving the greatest number of ions.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(ii) The number of solute particles in solution.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(i) Methanol and acetone.

Explanation: The interaction (A-A)* is greater than the interaction (A-B)*. Methanol has greater intermolecular hydrogen bonding than methanol and acetone combined. As a result, methanol and acetone mixes will deviate from Raoult's law in a favourable way. The (A-A)* interaction is the interaction of acetone particles/molecules that do not have any hydrogen bonds between them.

The interaction between the particles / molecules of acetone and methanol is known as the (A-B)* interaction.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(ii) Low atmospheric pressure

Explanation:  The atmospheric pressure drops at high altitude, reducing the solubility of oxygen in blood and tissues.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(iii) Pressure

Explanation:  Because solids and liquids are nearly incompressible, the solubility of a solid in a liquid is unaffected by pressure.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(ii) Supersaturated

Explanation:  At a certain temperature, a supersaturated solution contains less than the maximum quantity of solute per given amount of solvent. When a small amount of solute is added to a solution like this, it precipitates/crystallizes quickly. A supersaturated solution varies from an unsaturated solution in that it does not precipitate or crystallise when a tiny amount of solute is added to it; instead, it goes into solution and remains dissolved at a specific temperature.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(iii) Equal to the rate of crystallisation

Explanation : This occurs under equilibrium conditions, i.e. rate of forward reaction (dissolution) = rate of backward reaction (crystallisation).

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(iv) Powdered sugar in hot water.

Explanation: (i) The solubility of a solute/sugar particle increases as its surface area increases. Powdered sugar dissolves more quickly due to its increased surface area.

(ii) Because it provides a cool sensation when touched, sugar dissolving is an endothermic process. Increasing the temperature or using hot water, according to LeChatelier's theory, facilitates sugar breakdown.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(i) Mole fraction

Explanation:  The mole fraction (x) is important for determining the relationship between a solution's concentration and its vapour pressure. Rault's law states that p1 = x1 po1 in a binary solution of two volatile liquids, where p1 is the vapour pressure of component 1, x1 is its mole fraction in solution, and po1 is the vapour pressure of pure solvent.

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