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The elevation in boiling point for 1 molal solution of non-volatile solute A is 3K. The depression in freezing point for 2 molal solution of A in the same solvent is 6 K. The ratio of Kb and Kf i.e. Kb/Kf is 1 : X. The value of X is [nearest integer]
The elevation in boiling point for 1 molal solution of non-volatile solute A is 3K. The depression in freezing point for 2 molal solution of A in the same solvent is 6 K. The ratio of Kb and Kf i.e. Kb/Kf is 1 : X. The value of X is [nearest integer]
Match List – I and List – II.
Choose the correct answer from the options given below
Match List – I and List – II.
Choose the correct answer from the options given below
A gaseous mixture of two substances A and B, under a total pressure of 0.8 atm is in equilibrium with an ideal solution. The mole fraction of substance A is 0.5 in the vapour phase and 0.2 in the liquid phase. The vapour pressure of pure liquid A is_________atm. (Nearest integer)
A gaseous mixture of two substances A and B, under a total pressure of 0.8 atm is in equilibrium with an ideal solution. The mole fraction of substance A is 0.5 in the vapour phase and 0.2 in the liquid phase. The vapour pressure of pure liquid A is_________atm. (Nearest integer)
At , the vapour pressure of a solution containing 1 mole of -hexane and 3 moles of -heptane is of . At the same temperature, if one more mole of -heptane is added to this solution, the vapour pressure of the solution increases by of . What is the vapour pressure in of -heptane in its pure state ?
At , the vapour pressure of a solution containing 1 mole of -hexane and 3 moles of -heptane is of . At the same temperature, if one more mole of -heptane is added to this solution, the vapour pressure of the solution increases by of . What is the vapour pressure in of -heptane in its pure state ?
The vapour pressure of two volatile liquid A and B at 25°C are 50 Torr and 100 Torr, respectively. If the liquid mixture contains 0.3 mole fraction of A, then the mole fraction of liquid B in the vapour phase is <!-- [if gte mso 9]><xml>
</xml><![endif]--> The value of x is____________.
The vapour pressure of two volatile liquid A and B at 25°C are 50 Torr and 100 Torr, respectively. If the liquid mixture contains 0.3 mole fraction of A, then the mole fraction of liquid B in the vapour phase is <!-- [if gte mso 9]><xml>
Mole fraction of A in liquid phase, xA = 0.3
Mole fraction of B in liquid phase, xB = 0.7
Now;
= 100 × 0.7 = 70 torr
Mole fraction of B in vapour phase,
X = 14
If O2 gas is bubbled through water at 303 K, the number of millimoles of O2 gas that dissolve in 1 litre of water is______________. (Nearest integer)
(Given: Henry’s Law constant for O2 at 303 K is 46.82 k bar and partial pressure of O2 = 0.920 bar)
(Assume solubility of O2 in water in too small, nearly negligible)
If O2 gas is bubbled through water at 303 K, the number of millimoles of O2 gas that dissolve in 1 litre of water is______________. (Nearest integer)
(Given: Henry’s Law constant for O2 at 303 K is 46.82 k bar and partial pressure of O2 = 0.920 bar)
(Assume solubility of O2 in water in too small, nearly negligible)
According to Henry’s law
P = KH × mole fraction of solute
Mole of O2 = 1.09 × 10-3
A solution was made by adding of . The normality of the solution is . The value of is (The atomic mass of is )
A solution was made by adding of . The normality of the solution is . The value of is (The atomic mass of is )
A solution containing 2.5 × 10-3 kg of solute dissolved in 75 × 10-3 kg of water boils at 373.535 K. The molar mass of the solute is_________g mol-1. (nearest integer)
[Given Kb(H2O) = 0.52 K kg mol-1 and boiling point of water = 373.15 K)
A solution containing 2.5 × 10-3 kg of solute dissolved in 75 × 10-3 kg of water boils at 373.535 K. The molar mass of the solute is_________g mol-1. (nearest integer)
[Given Kb(H2O) = 0.52 K kg mol-1 and boiling point of water = 373.15 K)
Mass of solute ; wB = 2.5 × 10-3 kg
Mass of solvent,
Boiling point of solution ;
Boiling point of water ;
So, elevation in boiling point,
&
Assertion: When a solution is separated from the pure solvent by a semipermeable membrane, the solvent molecules pass through it from pure solvent side to the solution side.
Reason: Diffusion of solvent occurs from a region of high concentration solution to a region of low concentration solution.
Assertion: When a solution is separated from the pure solvent by a semipermeable membrane, the solvent molecules pass through it from pure solvent side to the solution side.
Reason: Diffusion of solvent occurs from a region of high concentration solution to a region of low concentration solution.
This is a assertion and reason answer type question as classified in NCERT Exemplar
(ii) Assertion and reason both are correct statements but reason is not correct
Explanation for assertion.
Explanation: Assertion is correct statement but reason is a wrong statement because a semipermeable

