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New answer posted
2 months agoContributor-Level 10
Volume of H2 adsorbed =
Therefore volume of gas adsorbed per gram of the adsorbent =
New answer posted
2 months agoContributor-Level 10
Mass = d * v = 1.02 * 1.2 = 1.224gm
Moles of acetic acid = 0.0204 moles in 2L
So molality = 0.0102 mol/kg
i = 1 + a for acetic acid
0.0198 = (1 + a) * 1.85 * 0.0102
α = 0.04928 = 5%
New answer posted
2 months agoContributor-Level 10
Mole fraction of A in liquid phase, xA = 0.3
Mole fraction of B in liquid phase, xB = 0.7
Now;
= 100 * 0.7 = 70 torr
Mole fraction of B in vapour phase,
X = 14
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