Solutions

If a solution containing more than 0.9% salt is used, and we place blood cells in it, the water will flow out of the cells, and they will shrink. Such a solution is a hypertonic solution.

Similarly, if a solution contains less than 0.9% salt, the water will flow into the cells, and they will enlarge. 

When more solute can be dissolved in a solution at a constant temperature, it is an unsaturated solution.

When no more solute can be dissolved in a solution at a constant temperature and pressure, it is called a saturated solution.

Y_A = p_a /p_a + p_b = 400 x ½ / 400 x ½ + 500 x ½ = 4/9

$\Delta T_f=K_f*m*i$  

0.93 = 1.86 * 1 * i

i =  $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$  

$i=1+\left(\frac{1}{n}-1\right)$

$\therefore n=2$            

$\Delta T_b=i{K}_{b}m$

$\Delta T_f=i{K}_{f}m$

$\therefore \frac{4}{4}=\frac{K_b*1.5}{K_f*4.5}$

$\frac{K_b}{K_f}=3$

$P_A^0=50torr$  

$P_B^0=100torr$  

Mole fraction of A in liquid phase,           x_A = 0.3

Mole fraction of B in liquid phase,            x_B = 0.7

Now;     $P_A=P_A^0{x}_A$  

$P_B=P_B^0{x}_B$

= 100 * 0.7 = 70 torr

Mole fraction of B in vapour phase,   $y_B=\frac{P_B}{P_A+P_B}=\frac{70}{85}$  

$\frac{70}{85}=\frac{x}{17}$  

                             X = 14

$\Delta T_b=i{K}_{b}m$

$\Delta T_f=i{K}_{f}m$

$\therefore \frac{4}{4}=\frac{K_b*1.5}{K_f*4.5}$

$\frac{K_b}{K_f}=3$

$m=\frac{w*1000}{molecularwt*w_{solvent}}=\frac{10.2*1000}{176*150}$

$=\frac{1020\cancel{0}}{176*15\cancel{0}}=0.386$

$\Delta T_f=K_f*m$

3.9 * 0.386

$\therefore x*10^{-1}=15.05*10^{-1}$

Ans = 15