Solutions

After the 2023-24 revised CBSE syllabus, many chapters have been removed, and in some chapters syllabus is reduced. As per the latest CBSE exam pattern 2025-26, the Chapter 1 Solutions will be asked for 5-7 marks in the Class 12 Chemistry CBSE board exams.

For other competitive exams, the Solutions c

NCERT offers the foundation for every class 12 student. CBSE board exam questions are primarily based on the NCERT exercise, Examples and conceptual explanation.

There are various benefits of using NCERT Solutions. 

• Specially for CBSE Board students, these NCERT Solutions are the best resource to

Shiksha focuses on completely fulfilling the needs of CBSE class 12 board students. We provide NCERT Solutions for classes 11th and 12th in class for physics, chemistry and mathematics.

Here are the key reasons why you should use Shiksha's NCERT Solutions for the Solution Chapter: 

• Complete cover

If a solution containing more than 0.9% salt is used, and we place blood cells in it, the water will flow out of the cells, and they will shrink. Such a solution is a hypertonic solution.

Similarly, if a solution contains less than 0.9% salt, the water will flow into the cells, and they will enlarge.

When more solute can be dissolved in a solution at a constant temperature, it is an unsaturated solution.

When no more solute can be dissolved in a solution at a constant temperature and pressure, it is called a saturated solution.

Y_A = p_a /p_a + p_b = 400 x ½ / 400 x ½ + 500 x ½ = 4/9

$\Delta T_f=K_f\times m\times i$  

0.93 = 1.86 × 1 × i

i =  $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$  

$i=1+\left(\frac{1}{n}-1\right)$

$\therefore n=2$            

$\Delta T_b=i{K}_{b}m$

$\Delta T_f=i{K}_{f}m$

$\therefore \frac{4}{4}=\frac{K_b\times 1.5}{K_f\times 4.5}$

$\frac{K_b}{K_f}=3$