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New answer posted

2 weeks ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

P A 0 = 5 0 t o r r  

P B 0 = 1 0 0 t o r r  

Mole fraction of A in liquid phase,           xA = 0.3

Mole fraction of B in liquid phase,            xB = 0.7

Now;     P A = P A 0 x A  

P B = P B 0 x B

= 100 * 0.7 = 70 torr

Mole fraction of B in vapour phase,   y B = P B P A + P B = 7 0 8 5  

7 0 8 5 = x 1 7  

                             X = 14

 

New answer posted

2 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Δ T b = i K b m

Δ T f = i K f m

4 4 = K b * 1 . 5 K f * 4 . 5

K b K f = 3

New answer posted

3 weeks ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

m = w * 1 0 0 0 m o l e c u l a r w t * w s o l v e n t = 1 0 . 2 * 1 0 0 0 1 7 6 * 1 5 0

= 1 0 2 0 0 1 7 6 * 1 5 0 = 0 . 3 8 6

Δ T f = K f * m

3.9 * 0.386

x * 1 0 1 = 1 5 . 0 5 * 1 0 1

Ans = 15

New answer posted

3 weeks ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Let we take 1 l  of solution

 Mass of solute = Volume * Density

= 0.5 m l * 1 . 0 5 g m / m l  

= 0.525 gram

Mass of solution = 1 kg. [considering very dilute solution]

Mass of solvent = 1000 – 0.525 = 999.475 gram

i = 1 . 9  

New answer posted

3 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

i = m t h e o r m a p p = 3 0 m a p p

Δ T b = i k b . m ] H A m x m = H + x + A x

0 . 0 1 5 6 = ( m * x m ) * 0 . 5 2 * m

m + x = 0.03

x = 0 . 0 1 i = 1 . 5 = 3 0 m a p p m a p p p = 2 0

 

New question posted

3 weeks ago

0 Follower 2 Views

New question posted

3 weeks ago

0 Follower 2 Views

New answer posted

3 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

At pH = 6.4

As in case of H2CO3,

pH = pKa it will be only when

[weak acid] = [conjugate base].

In case of 2

H2PO-4 |HPO2-4

New answer posted

3 weeks ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Solute and solvent both should obey Raoult's law

New answer posted

3 weeks ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Molarity =   moles of    solute     volume of solution in   L = 1 * 1.15 1342 * 1000 = 0.86 M

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