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New answer posted

10 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Total pressure of mixture =   P T o t a l = X A * P A o + X B * P B o = 9 0 * 0 . 6 + 1 5 * 0 . 4 = 6 0 m m

Mole fraction of B in vapour phase, ( X B ' ) = X B * P B o P T o t a l

X B ' = 0 . 4 * 1 5 6 0 = 0 . 1 = 1 * 1 0 1  

New answer posted

10 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

KCl solution has molality (m) = 3.3, [Means 3.3 mol of KCl dissolved in 1 kg of solved]

Total mass of solution = mass of solute + mass of solvent

= 3.3 * 74.5 + 1000 gm

= 1245.85 gm

Volume of solution = M a s s d e n s i t y = 1 2 4 5 . 8 5 1 . 2 = 1 0 3 8 . 2 0 m l

M = m o l e s * 1 0 0 0 V ( m l ) = 3 . 3 * 1 0 0 0 1 0 3 8 . 2 = 3 . 1 7 M          

Ans. = 3 (the nearest integer)

New answer posted

10 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

All the solution have higher ion production with respect to 0.1 M C2H5OH i.e. 0.1 M Ba3 (PO4)2, 0.1 M Na2SO4, 0.1 M KCl and 0.1 M Li3PO4. Hence all have lowered freezing point than 0.1 M C2H5OH (which is non-ionisable in aqueous medium).

Ans. = 4

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Δ T f = 0 . 2 ° C

m = 0 . 7 * 1 0 0 0 9 3 * 4 2 = 7 0 0 9 3 * 4 2 = 0 . 1 7 9 m

Δ T f = i K f m

i = Δ T f K f * m = 0 . 2 1 . 8 6 * 0 . 1 7 9 = 0 . 6

α 2 = 1 0 . 6 = 0 . 4

α = 0 . 4 * 2 = 0 . 8

% of = 80%

New answer posted

11 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

  Δ T b = i * K b * m

 or Δ T b = K b * m   (i = 1 for non-electrolyte)

  o r ( Δ T b ) A ( Δ T b ) B = ( K b ) A ( K b ) B

  o r x y = 1 8 | y = 8 |              

New answer posted

11 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Molality itself a strength representing terms for solution which does not depend upon the temperature.

 

New answer posted

11 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Let we take  of solution

Mass of solute = Volume * Density

= 0.5 m l * 1 . 0 5 g m / m l

= 0.525 gram

Mass of solution = 1 kg. [considering very dilute solution]

Mass of solvent = 1000 – 0.525 = 999.475 gram

i = 1 . 9

 

New answer posted

11 months ago

0 Follower 62 Views

A
alok kumar singh

Contributor-Level 10

C 6 H 1 2 O 6 G l u c o s e

M a s s o f C m a s s o f g l u c o s e = 7 2 1 8 0

% of C = 10.8 = M a s s o f C m a s s o f s o l u t i o n * 1 0 0

1 0 . 8 * 2 5 0 1 0 0 m a s s o f C

M o l a r i t y = 0 . 3 7 5 0 . 1 8 2 5 = 2 . 0 5 5 = 2 . 0 6

New answer posted

11 months ago

0 Follower 54 Views

V
Vishal Baghel

Contributor-Level 10

P 0 P S P 0 = n s o l u t e n s o l v e n t

P 0 P 0 2 P 0 = n s o l u t e n s o l v e n t

n s o l u t e = n s o l v e n t 2 = 1 0 0 1 8 * 2 = 2 . 7 8 m o l

New answer posted

11 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

ΔTf=Kf*m

(156155.1)=2*1.8MW*1000 (62.5*0.8)

0.9 = 2*1.8*1000MW*50

MW=80gm/mol

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