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New answer posted

10 months ago

0 Follower 11 Views

R
Raj Pandey

Contributor-Level 9

The vapour pressure of solution will be less than vapour pressure of pure solvent, so some vapour molecules will get condensed to maintain new equilibrium.

New answer posted

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Fact based    

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Vapour pressure over solvent is greater than that over solution.

New answer posted

10 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

The above mixture will show positive deviation from Raoult's law.                                                     

New answer posted

10 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

Let volume of solution = x ml
So mass of solution = 1.2x
And mass of water = x gm
Mass of solute = 0.2x
Molality = (W_solute * 1000) / (M_solute * W_solvent) = (0.2x * 1000) / (40 * x) = 5 m

New answer posted

10 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

? = CRT
2.42 * 10? ³ = ( (1.46/M_polymer) / 0.1 ) * 0.083 * 300
M_polymer = (1.46 * 0.083 * 300) / (2.42 * 10? ³ * 0.1)
= 14.96 * 10? gm = 15 * 10? gm

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

ΔTb = 0.6 K
ΔTb = Kb * m = Kb * (wt. * 1000)/ (mol wt. * Wsolvent (gm)
0.6 = 5 * (3 * 1000)/ (mol wt. * 100)
∴ mol wt. = (15 * 10)/ (0.6) = 1500/6
= 250 g/mole

New answer posted

10 months ago

0 Follower 14 Views

V
Vishal Baghel

Contributor-Level 10

  Δ T f = k f . m

T f 0 T f = 5 . 1 2 * ( 1 0 5 8 ) ( 2 0 0 1 0 0 0 )

    5.5 – Tf = 5 . 1 2 * 5 * 1 0 5 8  

  T f = 1 . 0 8 6 ° C = ( 1 . 0 8 6 ) ° C 1 ° C             

New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Depression in freezing point will be maximum for Al2 (SO4)3 since its Van't Hoff factor is the highest. So its solution will have the lowest freezing point.

New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

 

Hence, electronic configuration of CO2+ is [ A r ] 3 d 7 4 s 0 . In complex [ C o ( C N ) 6 ] 4 , given ligand CN- is strong hence, after pairing in d-subshell, total number of unpaired electron =

spin magnetic moment = 1 ( 1 + 2 ) = 3 = 1 . 7 3 B M = 1 . 7 3 B M 2 . 0 B M  

             

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