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New answer posted

3 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Solute and solvent both should obey Raoult's law

New answer posted

3 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Molarity =   moles of    solute     volume of solution in   L = 1 * 1.15 1342 * 1000 = 0.86 M

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

∴ % of S in the compound
= (32/233) * (mass of BaSO? / mass of compound) * 100 = (32 * 0.35 * 100) / (233 * 0.25) = 19.227 ≈ 19.23

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Let V ml is taken

  5 * V + 1 * 1 5 0 ( V + 1 5 0 ) + 0 . 9 = 2 . 5            

5V + 150 = 2.25 V + 337.5

V = 1 8 7 . 5 2 . 7 5 = 6 8 . 1 8 m l            

New answer posted

3 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

? Solvent is H? O, which is in excess

So using m ( molality ) = (x? *1000)/ (x? * (M? )? )

? x? = 0.74 (Mol? = 18 g)

x? = 1 – 0.74 = 0.26 ∴ m = (0.26 * 1000)/ (0.74 * 18) = 19.5

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

W = 4.5 g

M.W = 90

V = 250 ml

Using M = W M . W * V * 1 0 0 0  

M = 4 . 5 9 0 * 2 5 0 * 1 0 0 0 = 0 . 2       

M = 2 * 10-1 M

So, x = 2

New answer posted

3 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

ppm of O? = (wt. of O? ) / (wt. of H? O) * 10?
= (10.3 mg) / (1.03 * 10? mg) * 10?
= 10ppm

New answer posted

3 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

i = total no. of particles after dissociation/association / total no. of particle before dissociation/association
HA? H? + A? (Dissociation)
0.5a
2HA → (HA)? (Association)
0.5a/2
i = (a + 0.25a)/a = 125 x 10? ²
Ans. = 125

New question posted

3 months ago

0 Follower 3 Views

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Molality = moles of solute / mass of solvent (kgs) ⇒ 1 = 0.5 / W (kgs)
Wsolvent (kgs) = 0.5 = 500 g

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