Solutions

Get insights from 207 questions on Solutions, answered by students, alumni, and experts. You may also ask and answer any question you like about Solutions

Follow Ask Question
207

Questions

0

Discussions

3

Active Users

0

Followers

New answer posted

7 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Equivalent of solute = 0.1 * 0.1
Mole of solute (Na? CO? ·xH? O) = [0.1 * 0.1]/2
Mass of Na? CO? ·xH? O = ( [0.1 * 0.1]/2) * [106 + 18x] = 1.43
⇒ 106 + 18x = 286
18x = 180
x = 10

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Osmosis.

New answer posted

7 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

The vapour pressure of solution will be less than vapour pressure of pure solvent, so some vapour molecules will get condensed to maintain new equilibrium.

New answer posted

7 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Fact based    

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Vapour pressure over solvent is greater than that over solution.

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 687k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.