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New answer posted
10 months agoContributor-Level 10
Relative lowering in vapour pressure depends on no. of mole of solute greater the no. of mole of solute greater in RLVP and smaller will be vapour pressure. So order of vapour pressure is B > C > A.
New answer posted
10 months agoContributor-Level 10
Π = iCRT = I (n/V)RT
Πfinal = (Π? V? + Π? V? )/ (V? + V? )
Πfinal = [ (0.1 * 1) + (0.2 * 2)]/3
= (0.1 + 0.4)/3 = 0.5/3 = (500/3) * 10? ³ atm
so X = 167
New answer posted
10 months agoContributor-Level 10
Equivalent of solute = 0.1 * 0.1
Mole of solute (Na? CO? ·xH? O) = [0.1 * 0.1]/2
Mass of Na? CO? ·xH? O = ( [0.1 * 0.1]/2) * [106 + 18x] = 1.43
⇒ 106 + 18x = 286
18x = 180
x = 10
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