Vector Algebra
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New answer posted
6 days agoContributor-Level 10
is collinear with
⇒ = …(1)
is collinear with
⇒ …(2)
From (1) and (2)
->
and are non-collinear
-> 1 + 5m = 0 and 6 – lm = 0 Þ lm = 6
-> l = – 30
Now,
On comparing
α = 5, β = 30 ⇒ α + β = 35
New answer posted
2 weeks agoContributor-Level 10
given are collinear then
Since are not collinear so
Hence possible unit vector parallel to it be for =
New answer posted
2 weeks agoContributor-Level 10
Mid point of BC is
For = 1, and will be collinear. So for non collinearity
= 2
New answer posted
2 weeks agoContributor-Level 10
Mid point of BC is
For a = 1, and will be collinear. So for non collinearity
a = 2
New answer posted
2 weeks agoRelated Tags
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