Work, Energy and Power

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Payal Gupta

Contributor-Level 10

6.13 The radius of the rain drop = 2 mm = 2 *10-3 m

The height of drop, s = 500 m

Density of water,  ?  = 103 kg/ m3

Mass of the rain drop = volume *density = (4/3) ? r3 *?  = 3.35 *10-5 kg

The gravitational force on the raindrop, F = mg = 3.28 *10-4 N

Work done by the gravity on the drop is = mgs where s = 250 m

Work done = 0.082 J

The work done during the second half will remain same.

The total energy of the raindrop will be conserved during the motion.

Total energy at the top

E1 = mgh where h = 500 m, E1 = 0.164 J

Due to resistive force, the energy of the drop on reaching the ground

E2 = (1/2)mv2 where

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Payal Gupta

Contributor-Level 10

6.12 Electron mass, me = 9.11*10-31 kg

Proton mass, madhya pradesh = 1.67*10–27 kg

Electron's kinetic energy = 10 keV = 10 * 103 * 1.60 *10–19 J = 1.60 *10–15 J

Proton's kinetic energy = 100 keV = 100 *103 * 1.60 *10–19 J = 1.60 *10–14 J

The electron kinetic energy is given by Eke = (1/2)m ve2 where ve is the velocity of electron

ve = ?   { (2 * Eke )/m} = 5.92 *107 m/s

The velocity of proton vp = ?   { (2 * Pke )/m} = 4.37 *106 m/s

The speed ratio = ve / vp = 13.5

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5 months ago

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Payal Gupta

Contributor-Level 10

6.11: Force exerted on the body, F =?  i? +2j?  +3 k?  N

Displacement, s = 4 km

Work done, W = F.s

= (?  i? +2j?  +3 k? ). (4k? )

= 0+0-3 *4

= 12 J

New answer posted

5 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

6.10 Power is given by the relation

P = Fv = mav = mv dvdt = constant ( say, k)

vdv = kmdt

v22=kmt

v = 2ktm

For displacement x of the body, we have:

v = dxdt = 2kmt1/2

dx = k' t1/2 dt where k' = 2k3 = constant

On integrating both sides, we get

x = 23k't3/2

Therefore x ? t3/2

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

6.9 Let us assume

Body mass = m

Acceleration = a

According to Newton's 2nd law F = MA (constant)

We know a = dv/dt = constant. Hence dv = dt * constant

On integrating, v = t + constant

The relation of power is given by P = F *v

We have v=u+at

Hence,  P=F* (u+at)

ma (u+at)

mau+ma2t

Therefore P ? t

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

6.8 (a) In elastic collision, the initial and final kinetic energy is equal. When the two balls collide, there is no conservation of kinetic energy; it gets converted into potential energy.

 

(b) The total linear momentum is conserved in an elastic collision.

 

(c) In case of inelastic condition in case (a), there will be loss of kinetic energy but in case of (b), the total linear momentum will be conserved in inelastic collision also.

 

(d) It is an elastic collision as the forces involves are conservative forces.

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Payal Gupta

Contributor-Level 10

6.7  (a) False. The total momentum and energy is conserved, not the individual.

 

(b) False. External forces can change the energy of a body.

 

(c) False. Only work done by conservative force over a closed loop is zero.

 

(d) True. In an inelastic collision, the final velocity reduces, resulting in loss of the initial kinetic energy.

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5 months ago

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Payal Gupta

Contributor-Level 10

6.6 (a) When a conservative force does positive work on a body, the body gets displaced in the direction of the force, it moves towards the centre of the force, thus resulting in decrease of potential energy.

 

(b) When the work done by a body against friction, it reduces its velocity. Hence kinetic energy decreases.

 

(c) The momentum cannot be changed by the internal forces on the system; the change of momentum is proportional to the external force.

 

(d) The total linear momentum does not change in an elastic collision.

New answer posted

5 months ago

6.5 Answer the following :

(a) The casing of a rocket in flight burns up due to friction. At whose expense is the heat

energy required for burning obtained? The rocket or the atmosphere?

 

(b) Comets move around the sun in highly elliptical orbits. The gravitational force on the comet due to the sun is not normal to the comet's velocity in general. Yet the work done by the gravitational force over every complete orbit of the comet is zero. Why ?

 

(c) An artificial satellite orbiting the earth in very thin atmosphere loses its energy gradually due to dissipation against atmospheric resistance, however small. Why then does its

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Payal Gupta

Contributor-Level 10

6.5 (a) As per the law of conservation of energy,

Total energy = potential energy + kinetic energy

= mgh + 12 mv2

When the casing burns, mass reduces, resulting in drop of energy. Hence the energy for burning of casing is drawn from the rocket.

 

(b) The force due to gravity is a conservative force. The work done on a closed path for a conservative force is zero. Hence, for every complete orbit of the comet, the work done by the gravitational force is zero.

 

(c) The potential energy of the satellite revolving the Earth decreases as it approaches the Earth and since the system's total energy should remain constant, the k

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Payal Gupta

Contributor-Level 10

6.4 Given, particle energy, E = 1 J,

Force constant, k = 0.5 N/m

Kinetic energy, KE = 12 mv2

From the equation, total energy, E = KE +PE, we get

1 = (1/2)mv2 + (1/2) kx2

when it turns back, v becomes 0

1 = (1/2) *0.5*x2 , x = ± 2

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