Tags Alcohol Phenol And Ethers

Alcohol Phenol And Ethers

Get insights from 260 questions on Alcohol Phenol And Ethers, answered by students, alumni, and experts. You may also ask and answer any question you like about Alcohol Phenol And Ethers

Follow Ask Question

260

Questions

Discussions

Active Users

Followers

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

Given below are two statements.

0 Follower 6 Views

alok kumar singh

Contributor-Level 10

There is no mirror image of each other, having some configuration.

0 0

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

Among the following marked proton of which compound shows lowest pK_a value?

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

0 0

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

A 1.84 mg sample of polyhydric alcoholic compound 'X' of molar mass 92.0 g/mol gave 1.344mL of H₂ gas at STP. The number of alcoholic hydrogens present in compound 'X' is_________.

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

Mole of polyhydric alcohol = $\frac{1.84 * 1 0^{- 3}}{92} = 2.0 * 1 0^{- 5} m o l e .$

Mole of H₂ gas produced = $\frac{1.344}{22400} = 6.0 * 1 0^{- 5} m o l e .$

No of -OH gp present = $\frac{6.0 * 1 0^{- 5}}{2.0 * 1 0^{- 5}} = 3$

0 0

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

A sample of 4.5mg of an unknown monohydric alcohol, R-OH was added to methylmagnesium iodide. A gas is evolved and is collected and its volume measured to be 3.1 mL. The molecular weight of the unknown alcohol is ____________ g/mol.

[Nearest integer]

0 Follower 3 Views

Payal Gupta

Contributor-Level 10

(Calculation is done considering STP condition)

$R O H + C H_{3} M g l \to C H_{4} + R O M g l$

No. of moles ROH = no. of moles of CH4

$\frac{4.5 * 1 0^{- 3}}{M} = \frac{31}{22400} \Rightarrow 32.52 \approx 33 g m / m o l e$

0 0

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

A 1.84 mg sample of polyhydric alcoholic compound 'X' of molar mass 92.0 g/mol gave 1.344mL of H₂ gas at STP. The number of alcoholic hydrogens present in compound 'X' is_________.

0 Follower 4 Views

Payal Gupta

Contributor-Level 10

Mole of polyhydric alcohol = $\frac{1.84 * 1 0^{- 3}}{92} = 2.0 * 1 0^{- 5} m o l e .$

Mole of H₂ gas produced = $\frac{1.344}{22400} = 6.0 * 1 0^{- 5} m o l e .$

No of OH gp present = $\frac{6.0 * 1 0^{- 5}}{2.0 * 1 0^{- 5}} = 3$

0 0

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

Hex-4- ene- 2-ol on treatment with PCC gives 'A' on reaction with sodium hypolodite gives 'B', which on further heating with soda lime gives 'C'. The compound 'C' is

0 Follower 1 View

alok kumar singh

Contributor-Level 10

0 0

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

The complete combustion of 0.492g of an organic compound containing 'C', 'H' and 'O' given 0.793g of CO₂ and 0.442g H₂O. The percentage of oxygen composition in the organic compound is __________. (nearest integer)

0 Follower 3 Views

alok kumar singh

Contributor-Level 10

Moles of C = moles of CO₂

= $\frac{0.793}{44} m o l$

Mass of C = $\frac{0.793}{44} * 12 g$

= 0.261g

Moles of H = 2 * $\frac{0.442}{18} m o l$

Mass of H = $2 * \frac{0.442}{18} * 1 g$

Total mass of compound = 0.492g (given)

So; mass of O = (0.492 – 0.216 – 0.049) g

= 0.227g

% of O = $\frac{0.227}{0.492} * 100$

= 46.14%

the nearest integer = 46

0 0

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

The major product of the given reaction is (where, Me is – CH₃)

0 Follower 4 Views

alok kumar singh

Contributor-Level 10

0 0

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

The number of chiral alcohol(s) with molecular formula C₄H₁₀O is__________.

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

0 0

New answer posted

2 months ago

Alcohol Phenol And Ethers Class 12th

Sulphur dioxide is one of the components of polluted air. SO₂ is also a major contributor to acid rain. The correct and complete reaction to represent acid rain caused by SO₂ is

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

Complete reaction of acid rain is

$2 S O_{2} + O_{2} + 2 H_{2} O \overset{}{\to} 2 H_{2} S O_{4} (a c i d r a i n)$

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
688k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Alcohol Phenol And Ethers

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience