Alcohol Phenol And Ethers

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Base is tert-butoxide thus favours elimination with 3° alkyl halide and gives alkene

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Payal Gupta

Contributor-Level 10

Consider the image below

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5 months ago

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P
Payal Gupta

Contributor-Level 10

There is no mirror image of each other, having some configuration.

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V
Vishal Baghel

Contributor-Level 10

G l y c e r o l Δ K H S O 4 A c r o l e i n ( P u n g e s t , s u f f o c a t i n g o d o u r )

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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Payal Gupta

Contributor-Level 10

Consider the image below

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5 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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A
alok kumar singh

Contributor-Level 10

There is no mirror image of each other, having some configuration.

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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alok kumar singh

Contributor-Level 10

Mole of polyhydric alcohol =  1 . 8 4 * 1 0 3 9 2 = 2 . 0 * 1 0 5 m o l e .

Mole of H2 gas produced = 1 . 3 4 4 2 2 4 0 0 = 6 . 0 * 1 0 5 m o l e .  

No of -OH gp present =  6 . 0 * 1 0 5 2 . 0 * 1 0 5 = 3

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