Amines
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New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: (B) Triethylamine
The structure of the given amines are shown below.
New answer posted
5 months agoContributor-Level 10
(i) Aromatic amines react with nitrous acid (prepared in situ from NaNO2and a mineral acid such as HCl) at 273 - 278 K to form stable aromatic diazonium salts e., NaCl and water.
(ii) Aliphatic primary amines react with nitrous acid (prepared in situ from NaNO2and a mineral acid such as HCl) to form unstable aliphatic diazonium salts, which further producealcohola and acid called as hydrochloric acid and evolution of nitrogen
(iii) Aliphatic amines are stronger bases than aromatic amines due to following reasons:
(a) The lone pair of electrons of the nitrogen atom of aromatic amines is involved in
conjugation with the π−
New answer posted
5 months agoContributor-Level 10
(i) Aromatic amines react with nitrous acid (prepared in situ fromNaNO2 and a mineral acid such as HCl) at 273 - 278 K to form stable aromatic diazonium salts i.e., NaCl and water. This reaction is widely used for preparation of variety of compounds.
(ii) Aliphatic primary amines react with nitrous acid (prepared in situ from NaNO2 and a mineral acid such as HCl) to form unstable aliphatic diazonium salts, which is very reactive, which further produce alcohol and HCl with the evolution of nitrogen gas.
New answer posted
5 months agoContributor-Level 10
Gabriel phthalimide synthesis is used for the preparation of aliphatic primary amines. It involves nucleophilic substitution (SN2) of alkyl halides by the anion formed by the phthalimide.But aryl halides do not undergo nucleophilic substitution with the anion formed by the phthalimide.
Therefore aromatic primary amines cannot be formed by gabriel phthalimide process.
New answer posted
5 months agoContributor-Level 10
1- C6H5NH2 + CHCl3 + KOH
It is a carbylamine reaction in which a isocyanide compound is formed along with side products of potassium chloride.Basically the name of reaction is given is due to formation of a foul smelling compound called as isocyanide.
2- C6H5N2Cl + H3PO2 + H2O
Benzenediazonium chloride is a very reactive compound which oxidises hypophosphorous acid to hypophosphoric acid and the reactant is reduced to benzene.
3- C6H5NH2 + H2SO4 (conc.)
Aniline undergoes sulphonation to anillium hydrogensulphate.
4- C6H5N2Cl + C2H5OH
Aniline is very activating group which undergoes reaction to give ortho and para product. But in acidic medium
New answer posted
5 months agoContributor-Level 10
It is given that compound 'C' having the molecular formula, C6H7N is formed by heating compound 'B' with Br2and KOH. This is a Hoffmann bromamide degradation reaction (in which isocyanide compound is formed). Therefore, compound 'B' is an amide and compound 'C' is an amine. The only amine having the molecular formula, C6H7N is aniline. Therefore, compound 'B' (from which 'C' is formed) must be benzamide.
Further, benzamide is formed by heating compound 'A' with aqueous ammonia. Therefore, compound 'A' must be benzoic acid. The given reactions can be explained with the help of the following equations:
New answer posted
5 months agoContributor-Level 10
(i) Ethyl iodide reacts with NaCN gives a substitution reactions to give propanitrile upon partial hydrolysis gives B, upon reaction with sodium hydroxide gives C.
(ii) Benzenediazoniumchloride gives nucleophilic substitution reactions gives A, upon hydrolysis the CN ion is replaced by OH ion which is less better leaving group gives B upon heating with ammonia gives C.
(iii) Ethylbromide gives nucleophilic substitution reactions gives B, upon reduction gives B followed by reacting with nitrous acid, i.e oxidation gives propanol.
(iv) Nitrobenzene upon reduction with iron/acid gives A, reacting with sodium nitrite giv
New question posted
5 months agoNew answer posted
5 months agoContributor-Level 10
(i) Carbylamine reaction
Carbylamine reaction is used as a test for the identification of primary amines. When aliphatic and aromatic primary amines are heated with chloroform and ethanolic potassium hydroxide, carbylamines (or isocyanides) are formed. These carbylamines have very unpleasant odours. Secondary and tertiary amines do not respond to this test.
For example,
(ii) Diazotisation
Aromatic primary amines react with nitrous acid (prepared in situ from NaNO2 and a mineral acid such as HCl) at low temperatures (273-278 K) to form diazonium salts. This conversion of aromatic primary amines into diazonium salts is known as diaz
New answer posted
5 months agoContributor-Level 10
Primary amine: A primary (1°) amine is an amine that has the following general structural formula. R= alkyl or aryl group Secondary amine: A secondary (2°) amine is an amine that has the following general structural formula. R1 and R2= alkyl or aryl group Tertiary amine: A tertiary amine is an amine that has the following structure R1, R2 and R3 are alkyl or aryl groups Identification of Primary, Secondary and Tertiary amines Primary, secondary and tertiary amines can be identified by the following test: Hinsberg's test: This is an excellent test for the identification of primary, secondary and tertiary amines. In this test, the amine is shaken with benzenesulphonyl chloride ( Hinsberg's reagent) in the presence of an excess of aqueous KOH solution when (i) A primary amine gives a clear solution which on acidification gives an N-alkylbenzene sulphonamide which is soluble in Due to the presence of strong electron withdrawing sulphonyl group in the sulphonamide, the H-atom attached to nitrogen can be easily released as a proton. So it is acidic and dissolves in alkali. (ii) A secondary amine reacts with Hinsberg's reagent to give a sulphonamide which is soluble in There is no H-atom attached to the N-atom in the sulphonamide Therefore it is not acidic and soluble in alkali. (iii) A Tertiary amine does not react with Hinsberg's reagent at all |
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