Amines

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: option (B and C) 

Certain mild reducing agents like hypophosphorous acid (phosphinic acid) or ethanol reduce diazonium salts to arenes and themselves get oxidised to phosphorous acid and ethanol, respectively.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: (A and B)

When aliphatic and aromatic primary amines are heated with chloroform and ethanolic potassium hydroxide, they form isocyanides or carbylamines, which have a foul odor. This reaction does not occur in secondary or tertiary amines.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: (A, B & C) 

Nitro compounds are reduced to amines by passing hydrogen gas through an acidic medium containing finely divided nickel, palladium, or platinum, as well as by reduction with metals in an acidic medium.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: (C and D) 

Chlorobenzene and bromobenzene are prepared by the sandmeyer's reaction. 

While fluorobenzene and iodobenzene are prepared by simple heating of diazonium salt with aqueous KI Solution.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: (D)

Aliphatic and arylalkyl primary amines can be prepared by the reduction of the corresponding nitriles with LiAlH₄

Heating alkyl halide with primary, secondary and tertiary amine can be prepared by reduction of LiAlH4 followed by treatment with water.

Heating alkyl halide with potassium salt of phthalimide followed by hydrolysis produces primary amine. This process is known as Gabriel phthalimide reaction. The number of carbon atoms in the chain of amines of product is same as reactant.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: (B)

Among primary, secondary, and tertiary amines, tertiary amines are the most volatile compounds as they don't have any strong intermolecular H-bonding between N-H like the primary and secondary amines have. 

So due to weak dipole-dipole interactions, (B) will be the most volatile. 

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: (A)  

The basic strength of an atom is determined by its electron-donating capacity; in this case, the amide is the most basic due to the presence of a negative charge and two lone pairs of electrons on the nitrogen atom.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: (D) 

Pyrrolidine is the strongest of two bases because the lone pair of nitrogen does not involve sin resonance, and the presence of two alkyl basic compounds increases the basic strength among the given four compounds.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans:  (D) 

Since phenol is the strongest acid among the four options listed above, it is the weakest Brönsted base. The stronger the acid, the weaker the conjugate base.

Amines have a strong tendency to accept electrons thus they are a strong bronsted base while phenol is the strongest acid among all, therefore as per the relation of conjugative strong acids and weak bases, phenol is the weakest base. 

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: (D)

Weak electrophile such as Diazonium cation readily reacts with electron-rich compounds which are having electron-rich compounds such as hydroxyl group, amino group. They don't react with electron-withdrawing groups like nitro groups. Therefore, nitrobenzene will not undergo an azo coupling reaction with benzene diazonium chloride.