Block D and F Elements

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Payal Gupta

Contributor-Level 10

E M n + 3 / M n + 2 o = 1 . 5 1 V

the strongest oxidizing agent have the highest reduction potential. So Mn3+ is the strongest oxidizing agent.

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Payal Gupta

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Cerium exists in two oxidation states (+3) and (+4)

Ce+4+eCe+3E0=1.61VCe+3+3eCeE0=2.336V

It exist as Ce+4 and acts like a strong oxidizing agent by gaining electrons

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Payal Gupta

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In acidic solution

3Mn+6O42+4H+2Mn+7O4+Mn+4O2+2H2O

Difference in oxidation state of Mn is product

= 7 – 4 = 3

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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alok kumar singh

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The value of crystal field spilitting energy  ( Δ 0 ) increases down the group. 5d series member will have more  Δ 0 compared to 3d series or 4d series member.

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Vishal Baghel

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N i 2 + + 2 d m g [ N i ( d m g ) 2 ] Rosy-red precipitate

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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Vishal Baghel

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Baking soda = NaHCO3

Washing soda = Na2CO3. 10H2O

Caustic soda = NaOH

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Payal Gupta

Contributor-Level 10

8.48 To calculate magnetic moment of the complex species, we use the spin formula:

μ =√n(n+2) BM

When n= 1

⇒ μ = √1(1+2)

⇒ u= √3⇒

u=1.73 BM

When n=2

⇒ μ = √2(2+2)

⇒ μ = √8

⇒ μ = 2.83 BM

When n= 3

⇒ μ = √3(3+2)

⇒ μ = 15

⇒ μ = 3.87 BM

When n = 4

⇒ μ = √ 4(4+2)

⇒ μ = √24

⇒ μ = 4.899 BM

When n= 5

⇒ μ = √5(5+2)

⇒ μ = √35

⇒ μ = 5.92 BM

1. [K4 [Mn(CN)6]

⇒μ = 2.2 BM (given)

 

We can see from the above calculation that the given value(2.2) is close to n=1. It means that it has only one unpaired electron Also in this complex Mn is in +2 oxidation state,i.e., as Mn2+.Thus when CN- ligands approach Mn2+ ion, The electrons in 3d do not pair up.

The atomic number of Manganese (Mn) is Z = 25

The electronic configuration of 25Mn= [Ar] 3d5 4s2

And, the electronic configuration of Mn2+=[Ar] 3d5

Thus CN- is a strong ligand.

The hybridization involved is d2sp3 forming inner orbital oc

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