Block D and F Elements

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5 months ago

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Payal Gupta

Contributor-Level 10

 Δt=hcλ=6.63*1034*3.08*108600*109

=6.63*3.08*1017600 J

=765.765*1021J

? 766*1021 J

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Payal Gupta

Contributor-Level 10

E M n + 3 / M n + 2 o = 1 . 5 1 V

the strongest oxidizing agent have the highest reduction potential. So Mn3+ is the strongest oxidizing agent.

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Payal Gupta

Contributor-Level 10

Cerium exists in two oxidation states (+3) and (+4)

Ce+4+eCe+3E0=1.61VCe+3+3eCeE0=2.336V

It exist as Ce+4 and acts like a strong oxidizing agent by gaining electrons

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Payal Gupta

Contributor-Level 10

In acidic solution

3Mn+6O42+4H+2Mn+7O4+Mn+4O2+2H2O

Difference in oxidation state of Mn is product

= 7 – 4 = 3

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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alok kumar singh

Contributor-Level 10

The value of crystal field spilitting energy  ( Δ 0 ) increases down the group. 5d series member will have more  Δ 0 compared to 3d series or 4d series member.

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Vishal Baghel

Contributor-Level 10

N i 2 + + 2 d m g [ N i ( d m g ) 2 ] Rosy-red precipitate

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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Vishal Baghel

Contributor-Level 10

Baking soda = NaHCO3

Washing soda = Na2CO3. 10H2O

Caustic soda = NaOH

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