Block D and F Elements
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2 months agoContributor-Level 10
the strongest oxidizing agent have the highest reduction potential. So Mn3+ is the strongest oxidizing agent.
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2 months agoContributor-Level 10
Cerium exists in two oxidation states (+3) and (+4)
It exist as Ce+4 and acts like a strong oxidizing agent by gaining electrons
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2 months agoContributor-Level 10
In acidic solution
Difference in oxidation state of Mn is product
= 7 – 4 = 3
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2 months agoNew answer posted
2 months agoContributor-Level 10
The value of crystal field spilitting energy increases down the group. 5d series member will have more compared to 3d series or 4d series member.
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2 months agoContributor-Level 10
Baking soda = NaHCO3
Washing soda = Na2CO3. 10H2O
Caustic soda = NaOH
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4 months agoContributor-Level 10
8.48 To calculate magnetic moment of the complex species, we use the spin formula:
μ =√n(n+2) BM
When n= 1 | ⇒ μ = √1(1+2) ⇒ u= √3⇒ u=1.73 BM |
When n=2 | ⇒ μ = √2(2+2) ⇒ μ = √8 ⇒ μ = 2.83 BM |
When n= 3 | ⇒ μ = √3(3+2) ⇒ μ = 15 ⇒ μ = 3.87 BM |
When n = 4 | ⇒ μ = √ 4(4+2) ⇒ μ = √24 ⇒ μ = 4.899 BM |
When n= 5 | ⇒ μ = √5(5+2) ⇒ μ = √35 ⇒ μ = 5.92 BM |
1. [K4 [Mn(CN)6]
⇒μ = 2.2 BM (given)

We can see from the above calculation that the given value(2.2) is close to n=1. It means that it has only one unpaired electron Also in this complex Mn is in +2 oxidation state,i.e., as Mn2+.Thus when CN- ligands approach Mn2+ ion, The electrons in 3d do not pair up.
The atomic number of Manganese (Mn) is Z = 25
The electronic configuration of 25Mn= [Ar] 3d5 4s2
And, the electronic configuration of Mn2+=[Ar] 3d5
Thus CN- is a strong ligand.
The hybridization involved is d2sp3 forming inner orbital oc
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