Block D and F Elements

The spin-only magnetic moment value of M³+ ion (in gaseous state) from the pairs Cr³⁺/Cr²⁺, Mn³⁺/Mn²⁺, Fe³⁺/Fe²⁺ and Co³⁺/Co²⁺ that has negative standard electrode potential, is________ B.M [Nearest integer]

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Contributor-Level 10

In given electrodes, only $E_{C r^{3 +} / C r^{2 +}}^{0}$ is negative

Cr (24) – [Ar] 4s¹3d⁵4p⁰

Number of unpaired electrons = 3

$μ = \sqrt[]{n (n + 2)} B M = \sqrt[]{3 (3 + 2)} B M = 3.97 B M \approx θ 4 B M$

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6 months ago

Among Co³⁺, Ti²⁺, V²⁺ and Cr²⁺ ions, one if used as a reagent cannot liberate H₂ from dilute mineral acid solution, its spin-only magnetic moment in gaseous state is _________ B.M. (Nearest integer)

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$C o^{3 +}$ $^{}$ will not get oxidized, so will not liberate H2 gas upon reaction with acidic solution.

No. of unpaired electron = 4

Spin only magnetic moment = $\sqrt[]{4 (4 + 2)} B M = \sqrt[]{24} B M \approx 5 B M$

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6 months ago

Consider the following metal complexes:

[Co(NH₃)₆]³⁺

[CoCl(NH₃)₅]²⁺

[Co(CN)₆]^3-

[Co(NH₃)₅(H₂O)]³⁺

The spin-only magnetic moment value of the complex that absorbes light with shortest wavelength is _____________. B.M (Nearest integer)

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Complex absorbing minimum wavelength of light means the value of $Δ$ for it is maximum.

That complex will be ${[C o {(C N)}_{6}]}^{3 -}$ ${_{}}^{}$

$C o^{3 +} \Rightarrow 3 d^{6} 4 s^{0} \Rightarrow t_{2} g^{6} e g^{0}$

No. of unpaired electron = 0

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6 months ago

The disproportionation of $M n O_{4}^{2 -}$ in acidic medium resultant in the formation of two manganese compounds A and B. If the oxidation state of Mn is B is smaller than that of A, then the spin-only magnetic moment $(μ)$ value of B in BM is___________.

(Nearest integer)

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$M n O_{4}^{- 2} \to A + B$

Oxidation state of Mn in B < A

$M n O_{4}^{- 2} + H^{+} \to M n O_{4}^{-} + M n O_{2}$

B is MnO₂

$∴$ Oxidation state of Mn = +4

$∴_{25} M n^{+ 4} = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{0} 3 d^{3}$

$∴$ unpaired electron = 3

Spin only magnetic moment $(μ)$

$= \sqrt[]{n (n + 2)} = \sqrt[]{3 (3 + 2)} = \sqrt[]{15}$

$= 3.87 \approx 4$

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6 months ago

If ${[C u {(H_{2} O)}_{4}]}^{2 +}$ absorbs a light of wavelength 600nm d-d transition, then the value of octahedral crystal field splitting energy for ${[C u {(H_{2} O)}_{6}]}^{2 +}$ will be_________* 10^-^21J. (Nearest Integer)

(Given: h = 6.63 * 10^-³⁴ Js and c = 3.08 * 10⁸ ms^-¹)

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$Δ_{t} = \frac{h c}{λ} = \frac{6.63 * 1 0^{- 34} * 3.08 * 1 0^{8}}{600 * 1 0^{- 9}}$

$= \frac{6.63 * 3.08 * 1 0^{- 17}}{600}$ J

$= 765.765 * 1 0^{- 21} J$

$? 766 * 1 0^{- 21}$ J

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6 months ago

Among the following, which is the strongest oxidizing agent?

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$E_{M n^{+ 3} / M n^{+ 2}}^{o} = 1.51 V$

the strongest oxidizing agent have the highest reduction potential. So Mn³⁺ is the strongest oxidizing agent.

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6 months ago

Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?

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Cerium exists in two oxidation states (+3) and (+4)

$\begin{array}{l} C e^{+ 4} + e^{-} \to C e^{+ 3} E^{0} = 1.61 V \\ C e^{+ 3} + 3 e^{-} \to C e E^{0} = - 2.336 V \end{array}$

It exist as Ce+4 and acts like a strong oxidizing agent by gaining electrons

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6 months ago

Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is ____________.

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In acidic solution

$3 \overset{+ 6}{M n} O_{4}^{2 -} + 4 H^{+} \to 2 \overset{+ 7}{M n} O_{4}^{-} + \overset{+ 4}{M n} O_{2} + 2 H_{2} O$

Difference in oxidation state of Mn is product

= 7 – 4 = 3

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7 months ago

The difference in oxidation state of chrominum in chromate and dichromate salts is _________.

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Kindly consider the following figure

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7 months ago