Block D and F Elements

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New answer posted

4 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go thorugh the solution

Calamine->ZnCO3

New answer posted

4 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Element

V

Ti

Mn

Sc

DaH/kJ mol–1

515

473

281

326

New answer posted

4 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Fe3O4 is a ferrimagnetic substance

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Zn2+ has no unpaired electron and colourless in aqueous solution.

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

In Ce & Eu (+3) oxidation state is more stable

C e + 4 + e C e + 3 ( R e d u c t i o n ) so CeO2 is oxidising agent

E u + 2 E u + 3 + e ( o x i d a t i o n ) so EuSO4 is reducing agent

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

M n 2 + t 2 g 1 1 1 e g 1 1

(Number of unpaired electron = 5)

μ S = 3 5 = 5 . 9 1 6

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Most basic oxide V2O3

Here V has +3 O.S. Hence V+3 -> [ A r ] 3 d 2  

two unpaired e- in d- subshell

 

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

From the given structure of CuSO. 5H2O Cu (II) ion and oxygen bonds are present but ligands coordinating with Cu (II) ion are not O and S both.

New answer posted

5 months ago

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R
Raj Pandey

Contributor-Level 9

Valence shell electronic configuration of Eu in +2 O.S is,

  E u 2 + = 6 s 0 4 f 7  

It has half filled f-sub shell and stable.

New answer posted

5 months ago

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R
Raj Pandey

Contributor-Level 9

IUPAC nomenclature of element with atomic no. 103 is uniltrium

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