Block D and F Elements
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6 months agoNew answer posted
6 months agoNumber of electrons present in 4f orbital of Ho³? ion is __________.
(Given atomic number of Ho = 67)
Contributor-Level 10
? Ho = [Xe] 4f¹¹ 6s²
∴ Ho? ³ = [Xe] 4f¹? 6s?
Number of electrons in 4f- subshell = 10
New answer posted
6 months agoContributor-Level 10
Using, µ = √n (n+2) B.M, n = number of unpaired electrons.
? Ti? ³ = 4s? 3d¹, unpaired electron = 1
µ = 1.73 B.M
? V? ² = 4s? 3d³, unpaired electron = 3
µ = 3.87 B.M
? Sc? ³ = 4s? 3d? , unpaired electron = 0
µ = 0 B.M
New answer posted
6 months agoDichromate ion is treated with base, the oxidation number of Cr in the product formed is-----------.
Contributor-Level 10
Dichromate ion converted to chromate ion in basic medium and oxidation number of Cr in is +6.
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