Block D and F Elements

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New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

Ethylene diamine, en is bidentate, chelating ligand. Chelating ligands increase stability due to higher entropy factor.

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

Eutrophication occurs when the water body becomes overly enriched with nutrients. Eutrophication leads to decrease in the level of dissolved oxygen (DO) in water bodies.

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

The greater stability of Cu²? (aq) rather than Cu? (aq) is due to the much more negative ΔhydH of Cu²? (aq) than Cu? , which more than compensates for the second ionisation enthalpy of Cu.

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10 months ago

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R
Raj Pandey

Contributor-Level 9

The E° value for Ce? /Ce³? is +1.74 V, which suggests that Ce? is a strong oxidant, reverting to its common +3 oxidation state. So, Ce³? is more stable than Ce?

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10 months ago

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R
Raj Pandey

Contributor-Level 9

The size of the Bk³? ion is less than the Np³? ion because Berkelium (Bk) lies beyond Neptunium (Np) in the actinoid series, and the size variation here is because of the actinoid contraction.

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10 months ago

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A
alok kumar singh

Contributor-Level 10

Inversion of Sucrose:
C? H? O? (Sucrose) + H? O - (Invertase)-> C? H? O? (Glucose) + C? H? O? (Fructose)

Fermentation of Glucose:
C? H? O? (Glucose) - (Zymase)-> 2C? H? OH (Ethanol) + 2CO?

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10 months ago

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A
alok kumar singh

Contributor-Level 10

KMnO? oxidizes alkanes that contain a tertiary hydrogen (3°H) to form tertiary alcohols.

n-alkanes, which do not contain tertiary hydrogens, are not oxidized by KMnO? under these conditions.

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10 months ago

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R
Raj Pandey

Contributor-Level 9

Functional group isomers

 

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V
Vishal Baghel

Contributor-Level 10

A divalent metal ion with an atomic number (Z) of 25 is Mn²?
Mn²? (Z=25) has the electronic configuration: 3d? 4s? (n=5, five unpaired electrons).
The magnetic moment (μ) is calculated as: μ = √ [n (n+2)] = √ [5 (5+2)] = √35 = 5.92 BM.

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10 months ago

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A
alok kumar singh

Contributor-Level 10

Gd: [Xe]4f?5d¹6s²
∴ Gd³? is [Xe]4f?
Also μ = √n (n + 2) B.M
= √7x9 B.M = 7.9 B.M

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