Chemistry

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V
Vishal Baghel

Contributor-Level 10

Both statements are correct independently but the reason is not the correct reason of the assertion.

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3 months ago

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V
Vishal Baghel

Contributor-Level 10

I - Cl bond is stronger than I-I bond due to additional electrostatic force between I and Cl.

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3 months ago

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V
Vishal Baghel

Contributor-Level 10

Li is used in making batteries, liquid Na is a coolant in nuclear reactors. Cs is used in photoelectric cells and KOH as a base is used to absorb acidic oxides like CO?

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New answer posted

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V
Vishal Baghel

Contributor-Level 10

IUPAC name of element with atomic number 119 is ununennium.

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V
Vishal Baghel

Contributor-Level 10

The oxidation state of K in KO? is (+1).

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R
Raj Pandey

Contributor-Level 9

K.E = φ - φ?
φ? = 3 eV = 3 * 1.6 * 10? ¹? J = 4.8 * 10? ¹? J
φ = hc/λ = (6.63 * 10? ³? * 3 * 10? ) / (248 * 10? ) J = 8 * 10? ¹? J
K.E = 8 * 10? ¹? - 4.8 * 10? ¹? = 3.2 * 10? ¹? J
Now using, λ = h / √ (2 K.E m)
λ = (6.63 * 10? ³? ) / √ (2 * 3.2 * 10? ¹? * 9.1 * 10? ³¹) m
λ = (6.63 * 10? ³? ) / (7.63 * 10? ²? ) m = 0.87 * 10? m = 8.7 Å
So, the nearest integer is 9.

New answer posted

3 months ago

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R
Raj Pandey

Contributor-Level 9

T? = 300 K; K? = 1 * 10? ³ s? ¹
T? = 200 K; K? =?
E_a = 11.488 kJ/mol
Using Arrhenius equation:
log (K? /K? ) = (E_a / 2.303R) * [ (T? - T? ) / (T? )]
log (K? / 10? ³) = (11.488 * 10³ / (2.303 * 8.314) * [ (-100) / (6 * 10? )]
log (K? / 10? ³) = -1
K? / 10? ³ = 10? ¹
K? = 10? s? ¹ or K? = 10 * 10? s? ¹

New answer posted

3 months ago

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R
Raj Pandey

Contributor-Level 9

The complex CoCl? ·4NH? is represented as [CoCl? (NH? )? ]Cl.
Here, 4 NH? are neutral monodentate ligands. So, 2 equivalents of ethylene diamine replace 4NH? since ethylene diamine is a didentate ligand.

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3 months ago

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R
Raj Pandey

Contributor-Level 9

ΔG° = -9.478 kJ/mol
Using ΔG° = -2.303 RT log K_p
-9.478 * 10³ = -2.303 * 8.314 * 495 log K_p
1 = log K_p ⇒ K_p = 10
Here, for the given reaction A (g)? B (g), K_p = K_c
Initial A = 22 mmol
At equilibrium A = 22 - x mmol; B = x mmol
K_c = [B] / [A] = (x/V) / (22-x)/V) = x / (22-x) = 10
x = 10 (22-x) ⇒ x = 220 - 10x ⇒ 11x = 220 ⇒ x = 20
So, mmol of B at equilibrium are 20.

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