Chemistry

m = 10 molal
K_b = 0.5 K kg mol? ¹
Using: ΔT_b = I K_b m
and α = (i - 1) / (n - 1)
n for AB? is 3; α = 0.1
0.1 = (i - 1) / (3 - 1) ⇒ I = 1.2
ΔT_b = 1.2 * 0.5 * 10 = 6 °C
So, boiling point of solution = 100 + 6 = 106 °C

A 6.5 molal solution means 6.5 moles of KOH is in 1 kg (1000 g) of solvent (H? O).
Moles of solute, n_B = 6.5
Mass of solute, W_B = 6.5 * 56 = 364 g
Mass of solvent, W_A = 1000 g
Mass of solution = 1364 g
Volume of solution = 1364 / 1.89 mL
Now, molarity = [6.5 / (1364 / 1.89)] * 1000 M = 9 M

Moles of carbon in organic compound = Moles of carbon in CO?
n_c = 420 / 44 moles
Mass of carbon in organic compound = (420 / 44) * 12 = 114.54 g
Moles of hydrogen in compound = 2 * moles of H? O
n_H = 2 * (210 / 18) moles
Mass of hydrogen = 2 * (210 / 18) g = 23.33 g
% of H = (23.33 / 750) * 100 = 3.11%
The nearest integer is 3.

Solubility product of A? X = 4S? ³
Where S? is the solubility of salt A? X.
Solubility product of MX = S? ²
Where S? is the solubility of MX.
Given 4S? ³ = 4 * 10? ¹² ⇒ S? = 10? M
Given S? ² = 4 * 10? ¹² ⇒ S? = 2 * 10? M
So, S? / S? = 10? / (2 * 10? ) = 50

The balanced equation is:
2MnO? + 5C? O? ²? + 16H? → 2Mn²? + 10CO? + 8H? O
So, the value of c (coefficient for H? ) = 16.

Edge length in bcc, a? = 27 Å
Let, Edge length in fcc be a? Å
Now, the same element crystallises in bcc as well as fcc.
For bcc: 4r = √3 a? ⇒ r = (√3 / 4) a?
For fcc: 4r = √2 a? ⇒ r = a? / (2√2)
So, (√3 / 4) a? = a? / (2√2)
(√3 / 4) * 27 = a? / (2√2)
a? = 33.13 Å
The nearest integer is 33.

Antihistamines are antacids and antiallergics

H? O? can act as both an oxidizing & reducing agent in both acidic & basic medium. In the hydrogen economy, energy is stored & transmitted in the form of dihydrogen.

Roasting is a process in which sulphur is removed as SO? gas from sulphide ores on heating in excess of oxygen.

Bismuth (Bi) is a metal in group 15. Its hydride is BiH? , which is the strongest reducing agent due to its the lowest thermal stability.