Chemistry

The size of the Bk³? ion is less than the Np³? ion because Berkelium (Bk) lies beyond Neptunium (Np) in the actinoid series, and the size variation here is because of the actinoid contraction.

(a) Haber's process is used for the synthesis of NH?
(b) Ostwald's process is used to synthesize HNO?
(c) Contact process is used for the synthesis of H? SO?
(d) Hall-Héroult process is used for the extraction of aluminium.

The enol form of acetone exists in less than 0.1% quantity, since its keto form is highly stable. But in the case of acetylacetone, the enol form is stabilized by intramolecular H-bonding, so its quantity increases to approximately 15%.
The intramolecular H-bond in the enol form of acetylacetone is shown.

DIBAL-H at low temperature in a non-polar solvent, followed by hydrolysis, reduces esters to an aldehyde and an alcohol as a byproduct. The reaction shown is:

Kindly consider the following Image 

First, the specific conductance (κ) is calculated (κ = conductance * cell constant), and units are converted. Then, the molar conductivity (Λ? ) is found using the formula Λ? = κ / Concentration, with all units in the SI system. The calculation yields 14.3 mS m² mol? ¹.
Answer: 14 (Rounded off)

The energy is calculated using the formula Δ? = hc/λ. Plugging in the values for Planck's constant (h), the speed of light (c), and the given wavelength gives an energy of 3.99 * 10? ¹? J. The answer is requested as a single digit.
Answer: 4 (in units of 10? ¹? J)

Using Raoult's Law, P_Total = P°_A·X_A + P°_B·X_B = (21 kPa * 1/3) + (18 kPa * 2/3) = 7 + 12 = 19 kPa.
Answer: 19 kPa

The reaction is Fe (s) + 2HCl (aq) → FeCl? (aq) + H? (g). 50 g of Fe corresponds to 0.89 moles, which produces 0.89 moles of H? (g). The work done by the gas is calculated using W = -Δn_gasRT. The work done by the gas is the positive value, 2218 J.
Answer: 2218 J