Chemistry

This problem involves the stoichiometry of acid-base neutralization.

o   For the reaction with H? PO? (a dibasic acid), 100 mL of NaOH is required.

o   For the reaction with H? PO? (a monobasic acid), 200 mL of NaOH is required.

In proteins, the secondary structure (such as α-helices and β-sheets) is stabilized by hydrogen bonds formed between the carbonyl oxygen of one peptide bond and the amide hydrogen of another.

The magnetic moment of an ion is determined by its number of unpaired electrons (n). For the given lanthanide ions:

o   Ce? has 0 unpaired electrons (4f? ).

o   Eu³? has 6 unpaired electrons (4f? ).

o   Gd³? has 7 unpaired electrons (4f? ).
Gd³? has the highest number of unpaired electrons and therefore the highest magnetic moment.

The Lassaign's test is a qualitative analysis method used to detect nitrogen, sulfur, phosphorus, and halogens in an organic compound. Copper (II) oxide is used to detect carbon. In the sodium fusion extract, halides (X? ) precipitate with AgNO? , and sulfide (S²? ) precipitates as black PbS.

Kindly go through the solution

Solubility of CdSO? is water ; S = 8 * 10? M
Using Ksp = S²
Ksp = 64 * 10? M
Now,
CdSO? Cd²? + SO? ²?
in H? SO? (0.01M)
Ksp = [Cd²? ] [SO? ²? ]
64 * 10? = S? (S? + 0.01)
S? << 0.01
So, S? = 64 * 10? M.

ΔG° = + 25.2 kJ / mol
Using ΔG° = -2.3 RT log Kp
25.2 * 10³ = - 2.3 * 8.3 * 400 log Kp

o   3.3 = log Kp
log (1 / 2*10³) = log Kp
Kp = 1 / (2*10³)
Using; Kp = Kc (RT)
1 / (2*10³) = Kc (0.083 * 400)? ¹

Moles of benzoic acid = 6.1 / 121 = 0.05
Theoretical moles of m- bromobenzoic acid = 0.05
Observed moles of m- bromobenzoic acid = 7.8 / 200 = 0.039
% yield = (0.039 / 0.05) * 100 = 78%

Half life, t? /? = 1min
Let, time of 99.9% completion of reaction be 't' min
Let the reaction is of first order
K = (2.303/t) log? ( [R]? / [R])
[R] = 0.001 [R]?
t = (2.303 * 3 min) / 0.693
t = 9.99 min
the nearest integer is 10.