Chemistry

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New answer posted

8 months ago

0 Follower 21 Views

P
Payal Gupta

Contributor-Level 10

On decreasing pressure of NO by a factor of '2' the rate of reaction decreases by a factor of '4'

 Order of reaction w.r.t 'NO' = 2

New answer posted

8 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

Meq of K2Cr2O7 = Meq of Fe2+

(Molarity * Volume * nf) of K2Cr2O7 = (molarity * volume * nf) of Fe2+

0.02 * 20 * 6 = M * 10 * 1

M = 0.24 M

Molarity = 24 * 10-2 M

New answer posted

8 months ago

0 Follower 8 Views

B
Baskaran M

Contributor-Level 9

Math calculation is important for BiPC students as it is used in:

1. Physics and chemistry problem-solving

2. Biology for statistical analysis and modeling

3. Medical and health sciences

4. Research and data analysis

Basic math skills can benefit BiPC students in their academic and professional pursuits.

New answer posted

8 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

Consider the image below

New answer posted

8 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

Rf0= distance travelled by the solute / / distance travelled by the solvent

(Rf)A=2.083.25 (Rf)B=1.053.25

(Rf)A (Rf)B=21

New answer posted

8 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

(Calculation is done considering STP condition)

ROH+CH3MglCH4+ROMgl

No. of moles ROH = no. of moles of CH4

4.5*103M=312240032.5233gm/mole

New answer posted

8 months ago

0 Follower 18 Views

P
Payal Gupta

Contributor-Level 10

In given electrodes, only ECr3+/Cr2+0 is negative

Cr (24) – [Ar] 4s13d54p0

Number of unpaired electrons = 3

μ = n ( n + 2 ) B M = 3 ( 3 + 2 ) B M = 3 . 9 7 B M θ 4 B M

 

New answer posted

8 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

XeO3 ⇒ Number of lone pair = 1

XeOF4 ⇒ Number of lone pair = 1

XeF6 ⇒ Number of lone pair = 1

New answer posted

8 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

For first order reaction,

ln (PP0)=k.t

K=3.465*104

t1/2=0.6933.465*104=2*105 sec

New answer posted

8 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

Δ H i o n i z a t i o n o f C H 3 C O O H = 5 5 . 3 ( 5 7 . 3 )

= 2 KJ/mole

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