Chemistry
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New answer posted
8 months agoContributor-Level 10
No. of moles =
Moles of benzaldehyde =
Mass of benzaldehyde = 5 * 10-2 *106 = 5.3 gm
= 530 * 10-2 gm
New answer posted
8 months agoNew answer posted
8 months agoContributor-Level 10
SO3 -> Sp2 Planar
BF3 -> Sp2 Planar
-> Sp2 Planar
SF4 -> Sp3d non-planar
H2O2 -> Sp3 Non-planar
PCl3 -> Sp3 Non –planar
[Al (OH)4]- -> Sp3 Non-planar
XeF4 -> Sp3d2 planar
XeO3 -> Sp3 Non-planar
-> Sp3 Non-planar
New answer posted
8 months agoContributor-Level 10
Bauxite = AlOx (OH)3-2x (where O < x < 1)
Siderite = FeCO3
Cuprite = Cu2O
Calamine = ZnCO3
Haemetite = Fe2O3
Kaolinite = Al2 (OH)4Si2O5
Malachite = CuCO3 Cu (OH)2
Magneite = Fe3O4
Sphalerite = ZnS
Limonite = Fe2O3.3H2O
New answer posted
8 months agoContributor-Level 10
Let x gm is burnt
Moles = x/280
Heat released by x/280 mol = 2.5 * 0.45 kJ
Heat released by 1 mol =
x = 35 gm
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